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使用Jackson在Java中使用不同的POJO反序列化JSON数组

[英]Deserialize JSON Array with different POJOs in java with Jackson

How can I deserialize this JSON structure ? 如何反序列化此JSON结构?

[
  {
    "page": 1,
    "per_page": "50"
  },
  [
    {
      "id": "IC.BUS.EASE.XQ",
      "name": "ion"
    },
    {
      "id": "OIUPOIUPOIU",
      "name": "lal alalalal"
    }
  ]
]

( I get this back from the WorldBank Api, it is a bit simplified, the exact response you find here ). (我是从WorldBank Api那里得到的,这有点简化了,您可以在此处找到确切的响应)。

The problem is, that i get an array of objects, where the first element is a POJO and the second element is an array of POJOs of a specific type. 问题是,我得到了一个对象数组,其中第一个元素是POJO,第二个元素是特定类型的POJO数组。

The only way that I found out to deserialize this is to be very generic which results in Lists and Maps. 我发现反序列化的唯一方法是非常通用,从而生成列表和地图。

List<Object> indicators = mapper.readValue(jsonString, new TypeReference<List<Object>>() {});

Is there a better way to deserialize this JSON to get an Array or a List, where the first element is of the Object "A" and the second a List of Objects "B" ? 有没有更好的方法反序列化此JSON以获取数组或列表,其中第一个元素是对象“ A”,第二个元素是对象列表“ B”?

If I were you, I would do something like this. 如果我是你,我会做这样的事情。 It's not possible to represent your data in a good way in one list on java without using a common base class. 如果不使用公共基类,就不可能在Java的一个列表中以良好的方式表示数据。 In your case this unfortunately is Object . 在您的情况下,不幸的是Object You can help a bit by manipulating the response list though. 您可以通过处理响应列表来有所帮助。

    ArrayNode arrayNode = (ArrayNode) mapper.readTree(this.getScrape().getScrapetext());

    A a = mapper.readValue(arrayNode.get(0), A.class);

    arrayNode.remove(0);

    List<B> b = mapper.readValue(arrayNode.toString(), new TypeReference<List<B>>()
    {
    });

Given that the structure is rather irregular, in that there is no Java class definition that structurally matches a JSON Array with magic type definitions for elements by index, you probably need to do 2-pass binding. 鉴于结构相当不规则,因为没有Java类定义在结构上将JSON数组与具有按索引的元素的魔术类型定义相匹配的Java定义,您可能需要进行两遍绑定。

First, you bind JSON into either List (or just Object ) or JsonNode . 首先,您将JSON绑定到List (或只是Object )或JsonNode And from that, you can use ObjectMapper.convertValue() to extract and convert elements into actual types you want. 然后,您可以使用ObjectMapper.convertValue()提取元素并将其转换为所需的实际类型。 Something like: 就像是:

JsonNode root = mapper.readTree(jsonSource);
HeaderInfo header = mapper.convertValue(jsonSource.get(0), 
   HeaderInfo.class);
IdNamePair[] stuff = mapper.convertValue(jsonSource.get(1),
   IdNamePair[].class);

would let you get typed values from original JSON Array. 可以让您从原始JSON数组获取类型化的值。

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