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计算多维数组中的唯一值

[英]Count unique values in a multi dimensional array

I have an array of data that I need to create a count for. 我有一个需要为其创建计数的数据数组。 The array gets build via a database connection. 该阵列通过数据库连接构建。

Array (
     [0]=array(
          [cause] => "Bob"
          [cause_month] =>'7/2014'
     )
     [1]=array(
          [cause] => "Tim"
          [cause_month] =>'7/2014'
     )
     [2]=array(
          [cause] => "Bob"
          [cause_month] =>'7/2014'
     )
     [3]=array(
          [cause] => "Bob"
          [cause_month] =>'7/2014'
     )
     [4]=array(
          [cause] => "Tim"
          [cause_month] =>'8/2014'
     )
     [5]=array(
          [cause] => "Tim"
          [cause_month] =>'8/2014'
     )
     [6]=array(
          [cause] => "Sally"
          [cause_month] =>'8/2014'
     )
)

To output an array that looks like this: 要输出如下所示的数组:

Array (
    [7/2014] => [Bob]=>3,[Tim]=>1
    [8/2014] => [Tim]=>2,[Sally]=>1
)

I have gone through several examples that give me unique causes by cause_month but have not been able to get the # of times that the cause was the same in that cause_month. 我已经查看了几个示例,这些示例按cause_month提供了独特的原因,但是无法获得该原因在那个cause_month中相同的次数。

Here is what i have taken from another post: 这是我从另一篇文章中摘录的内容:

$class_array = array();
foreach ($sb_array as $sa) {
    $class_array[$sa['cause_month']][] = array('cause' => $sa['cause']);
}

This outputs: 输出:

[7/2014] => Bob , Tim
[8/2014] => Tim , Sally

Which is really close, but I still need the count of each cause for each cause_month 这真的很接近,但是我仍然需要每个cause_month的每个原因的计数

This should work for you: 这应该为您工作:

Just also use the name ( cause ) as second dimension key and initialize it with 0 if it doesn't exists. 还要使用名称( cause )作为第二维密钥,如果不存在,则将其初始化为0。 Then just simply increment the count for each occurrence. 然后,只需简单地为每个事件增加计数。

$class_array = array();
foreach ($sb_array as $sa) {
    if(!isset($class_array[$sa['cause_month']][$sa["cause"]]))
        $class_array[$sa['cause_month']][$sa["cause"]] = 0;
    $class_array[$sa['cause_month']][$sa["cause"]]++;
}

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