如何从python中的哪个字典中查找哪个键

Question

(In python) I have two dictionaries which are present in a list . Then i retrieved the non matching keys from the two dictionaries wrt comparing keys only.

But now my requirement is how to know which key is from which dictionary

My Code

first = dict(a=1, b=2) 
second = dict(b=0, c=3) 
for i in range(1): 
    diff = set(first) ^ set(second) 
print diff 

Answer 1

This shall help you. You can edit your code like this:

first = dict(a=1, b=2) 
second = dict(b=0, c=3) 
for i in range(1): 
    diff = set(first) ^ set(second)
    key_of_first = set(first) - set(second)
    key_of_second = set(second) - set(first) 
print diff 
print key_of_first
print key_of_second

Let me know if it works for you or not.

Output

set(['a', 'c'])
set(['a'])
set(['c'])

However, there is not need of for loop. It is there just because your code was having it initially.

Answer 2

from __future__ import print_function

dict_one = {'a': 1, 'b': 2}
dict_two = {'b': 2, 'c': 3}

keys_only_in_dict_one = set(dict_one.keys()) - set(dict_two.keys())
print('Keys only in dict_one:', keys_only_in_dict_one)  # {'a'}

keys_only_in_dict_two = set(dict_two.keys()) - set(dict_one.keys())
print('Keys only in dict_two:', keys_only_in_dict_two)  # {c'}

all_non_matching_keys = keys_only_in_dict_one | keys_only_in_dict_two
print('All non-matching keys:', all_non_matching_keys)  # {'a', 'c'}

Answer 3

You could do this :

key="foo"

for i in arr: #arr is the list which contains the dictionaries
   if key in i.keys():
     print(i) # Or print something else