[英]how can I define a map accept different kind of value in thrift?
I define a struct with thrift: 我用节俭定义了一个结构:
struct QuerySetRecord {
1:string recordId,
2:string crawlerName,
3:string recordType,
4:map<string,string> dataMap,
5:i16 priority,
}
the problem is the dataMap
, I do not only want to accept string
value, I may still want to accept List
or Map
, such as map<string, list<string>> dataMap
. 问题是dataMap
,我不仅要接受string
值,我可能仍想接受List
或Map
,例如map<string, list<string>> dataMap
。 In other words, I want a type like the root Object
in Java, object
in python 换句话说,我想要一个类型,例如Java中的root Object
,Python中的object
Can I do this? 我可以这样做吗?
You would have to create your own Object
and list all possible classes in it. 您将必须创建自己的Object
并列出其中的所有可能的类。
union Object {
1: string str;
2: i32 number32;
}
(as I'm not sure how union implementation works in all langs I'd go with struct with all fields optional) (因为我不确定在所有语言中联合实现的工作方式,我会选择带有所有字段可选的struct)
struct Object {
1: optional string str;
2: optional i32 number32;
}
and then: map<string, Object>
然后: map<string, Object>
In Thrift you can't create 'accept all' field, as it could not be fully portable across languages, and that's one of key functionalities of Thrift. 在Thrift中,您无法创建“ accept all”(全部接受)字段,因为它不能跨语言完全移植,这是Thrift的主要功能之一。
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