字符串化列表分为两个单独的列表

Question

I have a stringified list that looks something like this: 我有一个字符串列表，看起来像这样：

'[a:1,b:1,c:2,a:3]'

I want to separate this into two lists. 我想将其分为两个列表。

['a','b','c','d'] and [1,1,2,3] ['a','b','c','d']和[1,1,2,3]

is there any pythonic way of doing this without using eval (it doesnt work anyways)? 是否有任何不使用eval的方式来执行此操作的Python方法（反正还是不起作用）？

Answer 1

You can use re.findall() to find the characters and numbers and zip function to separate them : 您可以使用re.findall()查找字符和数字，并使用zip函数将它们分开：

>>> a='[a:1,b:1,c:2,a:3]'

>>> import re
>>> zip(*re.findall(r'([a-z]):(\d)',a))
[('a', 'b', 'c', 'a'), ('1', '1', '2', '3')]

Answer 2

import re
zip(*re.findall(r'([a-z]):([0-9])', my_string))

Depending your use, you can also add some + : 根据您的用途，您还可以添加一些+ ：

>>> zip(*re.findall(r'([a-z]+):([0-9]+)', '[a:1,blabla:1,c:20,a:3]'))
[('a', 'blabla', 'c', 'a'), ('1', '1', '20', '3')]

Answer 3

Just to go a little bit further in the requirement to get a list of ints: 为了更进一步了解整数列表，您需要：

str = '[a:1,b:1,c:2,a:3]'
p,q = zip(*[(x,int(y)) for x,y in re.findall('([a-z]+):(\d+)', str)])