[英]QString split return list of empty strings
Using this regex B([^.]*)E
I am trying to get all the characters between B
and E
from 我正在尝试使用此正则表达式B([^.]*)E
从中获取B
和E
之间的所有字符
B23432|234|24EB23432|2834|234EB23432|2134|234E
Using Qt4.8 使用Qt4.8
QRegExp rx("B([^.]*)E");
rx.setMinimal(true);
QString str = "B23432|234|24EB23432|2834|234EB23432|2134|234E";
QStringList list;
list = str.split(rx);
qDebug() << list;
it prints a list of empty strings. 它显示一个空字符串列表。 Shouldn't it return all the strings between B
and E
? 它不应该返回B
和E
之间的所有字符串吗?
The main issue is that you are trying to split, but in fact you need to find all matches in a loop and get capturedTexts()[1]
s (or cap(1)
s). 主要问题是您试图拆分,但实际上您需要在循环中查找所有匹配项并获取capturedTexts()[1]
s(或cap(1)
)。
QRegExp rx("B([^E]*)E");
rx.setMinimal(true);
QString str = "B23432|234|24EB23432|2834|234EB23432|2134|234E";
QStringList list;
int pos = 0;
while ((pos = rx.indexIn(str, pos)) != -1) {
list << rx.cap(1);
pos += rx.matchedLength();
}
qDebug() << list;
This works as well. 这也可以。 If there is something wrong with this please let me know. 如果这有什么问题,请告诉我。
QRegExp rx("[B(.*)E]");
rx.setMinimal(true);
QString str = "B23432|234|24EB23432|2834|234EB23432|2134|234E";
QStringList list;
list = str.split(rx, QString::SkipEmptyParts);
qDebug() << list;
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