[英]How to get params in url , and it is array? yii2
I have url like this我有这样的网址
http://localhost/belajar4/web/index.php?r=data%2Fsingle&id=2&DataSearch[TANGGAL]=2015-08-04&DataSearch[TANGGAL_SELESAI]=2015-08-12
And I want to get DataSearch['Tanggal'] dan DataSearch[TANGGAL_SELESAI]我想得到 DataSearch['Tanggal'] dan DataSearch[TANGGAL_SELESAI]
I have tried for id with我试过用
Yii::$app->request->queryParams['id']
And it was success for it, but not with DataSearch['Tanggal']它是成功的,但不是 DataSearch['Tanggal']
When I try for DataSearch['Tanggal'] the error is当我尝试 DataSearch['Tanggal'] 时,错误是
Undefined index: DataSearch[TANGGAL]
I think it should have easy to answer but i am newbie for yii2 and i didnt find the solution yet我认为应该很容易回答,但我是 yii2 的新手,我还没有找到解决方案
You can get them from array like this:您可以像这样从数组中获取它们:
Yii::$app->request->queryParams['DataSearch']["TANGGAL_SELESAI"]
Yii::$app->request->queryParams['DataSearch']["TANGGAL"]
You can also use combination of ArrayHelper::getValue()
and Yii::$app->request->get()
with dot notation:您还可以使用ArrayHelper::getValue()
和Yii::$app->request->get()
:
use Yii;
use yii\helpers\ArrayHelper;
...
$value = ArrayHelper::getValue(Yii::$app->request->get(), 'DataSearch.TANGGAL_SELESAI');
The main advandage is you can avoid Undefined index
exception and change default value (third parameter).主要优点是您可以避免Undefined index
异常并更改默认值(第三个参数)。
Official docs:官方文档:
I had faced slimier issue & spent lots of time to get the value but somehow I found solution like below.我遇到了更棘手的问题并花了很多时间来获得价值,但不知何故我找到了如下解决方案。
// Trying to print the value // 尝试打印值
echo Yii::$app->request->queryParams['DataSearch']['"TANGGAL_SELESAI"'];
echo Yii::$app->request->queryParams['DataSearch']['"TANGGAL"'];
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