解析-Swift：连接查询

Question

I'm creating an iOs app with Swift and Parse.com. Unfortunately, i've a problem when I build my query.

What I want : I have a class with sport's players (with goals and passes). I would like to retrieve the player with the most goals and the player with the most passes. I have two columns in my Parse class : goals and passes.

So, for me, I would use

query_goals.limit = 1 
query_goals.orderByDescending("goals")

query_passes.limit = 1
query_passes.orderByDescending("passes")

and now I need to concat the two queries but I didn't find anything for that in swift iOS documentation...

Does anyone have an idea please ? :)

EDIT : I want to print the best scorer and passer in collectionView cells :

override func queryForCollection() -> PFQuery {
    let query = PFQuery(className: "liste_joueurs")
    query.limit = 1
    query.orderByDescending("goals")

    let query_passes = PFQuery(className: "liste_joueurs")
    query_passes.limit = 1
    query.orderByDescending("passes")

    let final_query = query + query_passes //Swift Concat to illustrate my purpose

    return final_query
}


override func collectionView(collectionView: UICollectionView, cellForItemAtIndexPath indexPath: NSIndexPath, object: PFObject!) -> PFCollectionViewCell? {
    let cell = collectionView.dequeueReusableCellWithReuseIdentifier("statsCell", forIndexPath: indexPath) as! StatsViewCell

    // First cell for best scorer 
    // Second cell for best passer
    return cell

}

In the final_query ,

Answer 1

let query = PFQuery(className : "SportsPlayers") // Im assuming your classname change it as needed 

// for highest  scorer 
query.orderByDescending("goals")
query.limit = 1 

// for highest passes
query.orderByDescending("passes")
query.limit = 1

Answer 2

Ok I just found a solution. I don't need to use queryForCollection and concatenate queries but create a query and use findObjectsInBackgroundWithBlock function in every cell of my collectionView.