如何将值从另一个表获取到PHP / MySQL中的另一个表

Question

First I should say my English is not perfect. I am using XAMPP 5.6.0.0

I have two tables, services and services_cat .

    -- Table structure for table `services_cat`

    CREATE TABLE IF NOT EXISTS `services_cat` 
   (`ser_cat_id` int(11) NOT NULL,
    `service_category` varchar(50) NOT NULL)

    -- Table structure for table `services`

    CREATE TABLE IF NOT EXISTS `services` 
    (`service_id` int(11) NOT NULL,
     `scid` int(11) NOT NULL,
     `service_title` varchar(50) NOT NULL,
     `service_statement` varchar(1000) NOT NULL,
     `service_photo` varchar(100) NOT NULL)

I want to show following data in one table.

service_id
ser_cat_id
service_category
service_title
service_statement

ser_cat_id and service_id are PRIMARY KEY s.

here ser_cat_id save into scid in the services table. This ser_cat_id save multiple times in the scid colomn. But service_title will be changed. There are different types of service_title , but the scid is same for that different service_title s. That scid comming from ser_cat_id from services_cat table.

I can pass ser_cat_id to scid from service_cat table and I can fetch (display) that scid . But I want to display that DISTINCT service_category name of the ser_cat_id (same as scid in services table).

Can you please help me ..

Following is my code.

    <?php
    include_once("conn.php");

    $sql = mysql_query("SELECT * FROM services_cat JOIN services ON services_cat.ser_cat_id = services.service_id GROUP BY service_category ");
    while($row = mysql_fetch_object($sql))
    {

        echo "<tr>
        <td><p class='table-p'>$row->scid</p></td>
        <td><p class='table-p'>$row->ser_cat_id</p></td>
        <td><p class='table-p'>$row->service_category = $row->scid</p></td>
        <td><p class='table-p'>$row->service_title</p></td>
        <td><p class='table-p'>$row->service_statement</p></td>

        <td><p class='table-p'><a href='service_edit.php?ide=$row->service_id'>Edit</a> |
        <a href='service_delete.php?idd=$row->service_id'>Delete</a></p></td>
        ";
    }
    ?>

Answer 1

Based on what you want, this is what you need:

SELECT s.service_id, c.ser_cat_id, c.service_category, s.service_title, s.service_statement 
FROM services_cat AS c 
INNER JOIN services AS s 
  ON c.ser_cat_id = s.scid 

Check this running example: http://sqlfiddle.com/#!9/013f7/3/0

Inside your loop, your $row will have this data, as you need.

$row['service_id']
$row['ser_cat_id']
$row['service_category']
$row['service_title']
$row['service_statement']

Answer 2

try to change,

$sql = mysql_query("SELECT * FROM services_cat JOIN services ON services_cat.ser_cat_id = services.service_id GROUP BY service_category ");

to

$sql = mysql_query("SELECT * FROM services_cat JOIN services ON services_cat.ser_cat_id = services.scid GROUP BY service_category ");