REST Web项目出现404错误

Question

I'm with this test project named CLAWS-Dicionario , and I'm trying to run it on Glassfish server (which is working flawlessly). All I have is that class:

package com.k19.restful.resources;

import javax.ws.rs.GET; 
import javax.ws.rs.Path; 
import javax.ws.rs.Produces;

@Path("/helloworld")
public class HelloWorldResource {

    @GET 
    @Produces("text/plain") 
    public String showHelloWorld() { 
        return "Olá mundo!"; 
    }
}

And this add at web.xml in order to incorporate Jersey to it

<servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
      <param-name>com.sun.jersey.config.property.packages</param-name>
      <param-value>com.k19.restful.resources</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

I've also added the following jersey libraries to my build-path:

asm-debug-all-5.0.3.jar
javax.ws.rs-api-2.0.1.jar
jersey-server.jar
org.osgi.core-4.2.0

So I run the project, and everything feels fine. But when I try to access this URL:

http://localhost:8080/CLAWS-Dicionario/helloworld

It returns a 404 error. I'm sure the host is congured at 8080 port (the URL localhost:8080 works just fine). So what is the problem?

EDIT: The server began to present another problems, which took me to that line of the domain.xml file:

 <application context-root="/CLAWS_-_Dicionário" object-type="user" name="CLAWS-Dicionario" directory-deployed="true" location="${com.sun.aas.instanceRootURI}/eclipseApps/CLAWS-Dicionario/">

Repare the CLAWS_-_Dicionário part. Would this be the real name of my project? I had to remove the accent in order the server to work, and I'm finding no more console response when running the project...and even if I try the URL http://localhost:8080/CLAWS_-_Dicionario/helloworld , the error is still there,so...just found it something important to point.

Answer 1

Depending on which Servlet version you use, you need:

For Servlet 2.x implementation:

• jersey-container-servlet-core.jar

For Servlet 3.x implementation:

• jersey-container-servlet.jar

org.glassfish.jersey.servlet.ServletContainer is not packaged in jersey-server.jar

According to the api doc for Class ServletContainer

If the initialization parameter is not present and a initialization parameter "jersey.config.server.provider.packages" is present (see ServerProperties.PROVIDER_PACKAGES) a new instance of ResourceConfig with this configuration is created. The initialization parameter "jersey.config.server.provider.packages" MUST be set to provide one or more package names. Each package name MUST be separated by ';'.

The parameter com.sun.jersey.config.property.packages have been replaced by jersey.config.server.provider.packages in version 2.x.

<init-param>
      <param-name>jersey.config.server.provider.packages</param-name>
      <param-value>com.k19.restful.resources</param-value>
</init-param>

In domain.xml , you should have the context-root representing the url path from where the application is accessible:

<application context-root="/CLAWS-Dicionario" object-type="user" name="CLAWS-Dicionario" directory-deployed="true" location="${com.sun.aas.instanceRootURI}/eclipseApps/CLAWS-Dicionario/">

letting you access your application from:

 http://localhost:8080/CLAWS-Dicionario/helloworld