密码包含至少6个字符，1个数字，1个字母和任何特殊字符的JavaScript正则表达式

Question

I am trying like this:

(/^(?=.*\\d)(?=.*[az])(?=.*[AZ]).{6,}$/)

but it is not working.

Answer 1

Your can use /^(?=.*\\d)(?=.*[a-zA-Z])(?=.*[!@#$%^&*()_+\\-=\\[\\]{};':"\\\\|,.<>\\/?]).{6,}$/ .

1. (?=.*\\d) for at least one digit
2. (?=.*[a-zA-Z]) for at least one letter
3. (?=.*[!@#$%^&*()_+\\-=\\[\\]{};':"\\\\|,.<>\\/?]) for at least one special character

Use match() to find pattern

 $('#text').keyup(function() { $(this).css('border', this.value.match(/^(?=.*\\d)(?=.*[a-zA-Z])(?=.*[!@#$%^&*()_+\\-=\\[\\]{};':"\\\\|,.<>\\/?]).{6,}$/) ? '5px solid green' : '5px solid red'); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <input type="text" id="text" /> 

Or you can also use test() to find match

 $('#text').keyup(function() { var re = new RegExp(/^(?=.*\\d)(?=.*[a-zA-Z])(?=.*[!@#$%^&*()_+\\-=\\[\\]{};':"\\\\|,.<>\\/?]).{6,}$/); $(this).css('border', re.test(this.value) ? '5px solid green' : '5px solid red'); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <input type="text" id="text" /> 

Answer 2

You need to remove the parenthesis from around the opening and closing / in your regular expression.

Also, it is possible you wanted to combine the [az] and [AZ] into [a-zA-Z] so that both upper and lower case letters don't have to found, just one of the two.

Answer 3

Try utilizing String.prototype.match

 var str1 = "abc1e."; var str2 = "abc1e "; // match special character; any character not digit , // not any alphanumeric character , including `_` , // not space character var res1 = str1.match(/[^\\d|\\w|\\s]/i); // if match found , concat digit , alphanumeric character // if resulting array length is 6 , return `true` , else return `false` res1 = !!res1 ? res1[0].concat(str1.match(/\\d+|\\w+/i)).length === 6 : false; var res2 = str2.match(/[^\\d|\\w|\\s]/i); res2 = !!res2 ? res2[0].concat(str1.match(/\\d+|\\w+/i)).length === 6 : false; console.log(res1, res2);