根据Swift中的参数返回不同类型的数据

Question

I have different clases, each one has their methods that return different types. I don't want to repeat myself writing the same thing over and over again - feels like a bad practice, and I want to know if is possible with one function return the objects depending on the parameter given in the function. As an example:

func myFunction(type: String) -> ?? {
   switch type {
       case myClass1:
           return objectTypeMyClass1
           break;
       case myClass2:
           return objectTypeMyClass2
           break;
       case myClass3:
           return objectTypeMyClass3
           break;
       default: 
           break;
   }
}

Is that a good practice? It is possible.

Answer 1

You can use enum as a container for a type (something similar to how Apple have done optionals):

enum TypeContainer {
    case SomeInt(Int)
    case SomeString(String)
    case SomeBool(Bool)

    init(int: Int) {
        self = .SomeInt(int)
    }

    init(string: String) {
        self = .SomeString(string)
    }

    init(bool: Bool) {
        self = .SomeBool(bool)
    }
}

let a = TypeContainer(string: "123")
let b = TypeContainer(int: 88)
let c = TypeContainer(bool: true)

switch a {
case .SomeInt(let i):
    println(i)
case .SomeString(let s):
    println(s)
case .SomeBool(let b):
    println(b)
default:
    break
}