将IP地址转换为十六进制

Question

How do I make the following conversion using python?

"172.1.3.1" >> "\xAC\x01\x03\x01"

currently I am able to make the following conversion:

"172.1.3.1" >> "AC010301"

However I require my results to have the hexadecimal escape characters as shown above.

Answer 1

You can use the socket module, if you are using Python 2.

>>> import socket
>>> socket.inet_aton("172.1.3.1")
'\xac\x01\x03\x01'

This utilizes inet_aton :

Convert an IPv4 address from dotted-quad string format (for example, '123.45.67.89') to 32-bit packed binary format, as a string four characters in length.

---

If you are using Python 3:

>>> import ipaddress
>>> ipaddress.IPv4Address("172.1.3.1").packed
b'\xac\x01\x03\x01'

Answer 2

>>> socket.inet_aton('172.1.3.1')
'\xac\x01\x03\x01'
>>> struct.pack('>I', IPy.IP('172.1.3.1').int())
'\xac\x01\x03\x01'