swift将Range <Int>转换为[Int]

Question

how to convert Range to Array

I tried:

let min = 50
let max = 100
let intArray:[Int] = (min...max)

get error Range<Int> is not convertible to [Int]

I also tried:

let intArray:[Int] = [min...max]

and

let intArray:[Int] = (min...max) as [Int] 

they don't work either.

Answer 1

您需要创建一个Array<Int>使用Range<Int> ，而不是投荷兰国际集团它。

let intArray: [Int] = Array(min...max)

Answer 2

将Range放在init中。

let intArray = [Int](min...max)

Answer 3

I figured it out:

let intArray = [Int](min...max)

Giving credit to someone else.

Answer 4

do:

let intArray = Array(min...max)

This should work because Array has an initializer taking a SequenceType and Range conforms to SequenceType .

Answer 5

Use map

let min = 50
let max = 100
let intArray = (min...max).map{$0}

Answer 6

Interesting that you cannot (at least, with Swift 3 and Xcode 8) use Range<Int> object directly:

let range: Range<Int> = 1...10
let array: [Int] = Array(range)  // Error: "doesn't conform to expected type 'Sequence'"

Therefore, as it was mentioned earlier, you need to manually "unwrap" you range like:

let array: [Int] = Array(range.lowerBound...range.upperBound)

Ie, you can use literal only.

Answer 7

Since Swift 3/Xcode 8 there is a CountableRange type, which can be handy:

let range: CountableRange<Int> = -10..<10
let array = Array(range)
print(array)
// prints: 
// [-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

It can be used directly in for - in loops:

for i in range {
    print(i)
}

Answer 8

You can implement ClosedRange & Range instance intervals with reduce() in functions like this.

func sumClosedRange(_ n: ClosedRange<Int>) -> Int {
    return n.reduce(0, +)
}
sumClosedRange(1...10) // 55

func sumRange(_ n: Range<Int>) -> Int {
    return n.reduce(0, +)
}
sumRange(1..<11) // 55