如何在sql查询中编写php代码？

Question

the code is like this 代码是这样的

$sql="SELECT tahun FROM tahunajar ";

i want the value of $sql can write in this query 我想要$ sql的值可以写在此查询中

$sql1= "SELECT * FROM soal where idSoal LIKE '-->HERE<--' ";

can someone tell me how do it? 有人可以告诉我怎么做吗？

Answer 1

当然，你可以这样写

$sql1= "SELECT * FROM soal where idSoal IN (".$sql.") ";

Answer 2

Simply use the variable in double quoted string. 只需在双引号字符串中使用变量。 It will work. 它会工作。 Following is the example: 以下是示例：

$sql1= "SELECT * FROM soal where idSoal LIKE $sql";

You can learn more from HERE . 您可以从此处了解更多信息。