提取名称和IP地址的shell脚本

Question

Is there a way to use shell script to get only the name and net from the result as below:

Result

6cb7f14e-6466-4211-9a09-2b8e7ad92703 | name-erkoev4ja3rv                              | 2e3900ff36574cf9937d88223403da77 | ACTIVE | Running     | net0=10.1.1.2; ing-net=10.1.1.3; net=10.1.1.4; 

Expected Result

name-erkoev4ja3rv: 10.1.1.4

Answer 1

$ input="6cb7f14e-6466-4211-9a09-2b8e7ad92703 | name-erkoev4ja3rv                              | 2e3900ff36574cf9937d88223403da77 | ACTIVE | Running     | net0=10.1.1.2; ing-net=10.1.1.3; net=10.1.1.4;"

$ echo "$input"  | sed -E 's,^[^|]+ \| ([^ ]+).* net=([0-9.]+).*$,\1: \2,g'
name-erkoev4ja3rv: 10.1.1.4

Answer 2

echo "6cb7f14e-6466-4211-9a09-2b8e7ad92703 | name-erkoev4ja3rv                              | 2e3900ff36574cf9937d88223403da77 | ACTIVE | Running     | net0=10.1.1.2; ing-net=10.1.1.3; net=10.1.1.4;"  | awk -F ' ' '{print $3}{print $13}' 

这是否满足您的要求？