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PHP:如何使用DomElement更改XML的一部分

[英]PHP: How to change part of XML using DomElement

I am trying to make a function that changes part of an XML using XPath. 我正在尝试制作一个使用XPath更改XML部分的函数。 I used part of someone else post: 我使用了其他人的帖子:

/*********************************************************************
Function to replace part of an XML
**********************************************************************/
function replacePartofXML($element, $methodName, $methodValue, $xml, $newPartofXML)
{
    $xpathstring = "//" . $element . "[@$methodName = \"$methodValue\"]";
    $xml->xpath($xpathstring);

    //$domToChange = dom_import_simplexml($xml->xpath($xpathstring));
    $domToChange = dom_import_simplexml($xml);
    $domReplace  = dom_import_simplexml($newPartofXML);
    $nodeImport  = $domToChange->ownerDocument->importNode($domReplace, TRUE);
    $domToChange->parentNode->replaceChild($nodeImport, $domToChange);

    return($xml);
}

What I want to do is return the appended XML. 我想做的是返回附加的XML。 I can't use dom_import_simplexml($xml->node->node) as my XML has many repeating element (but they have different ID reason why I am trying to use xpath) 我不能使用dom_import_simplexml($ xml-> node-> node),因为我的XML有很多重复元素(但是它们具有不同的ID,因此我尝试使用xpath)

The commented line does not work either as xpath returns an array and dom_import_simplexml is cannot import arrays. 注释行不起作用,因为xpath返回一个数组,而dom_import_simplexml无法导入数组。

Thanks for you input 感谢您的输入

You can take the first element returned by xpath() in case you believe the target element is unique (no-element-returned checking omitted) : 如果您认为目标元素是唯一的(可以省略无元素返回的检查),则可以采用xpath()返回的第一个元素:

$domToChange = dom_import_simplexml($xml->xpath($xpathstring)[0]);

or iterate through the return value of xpath() and replace one by one. 或遍历xpath()的返回值并一一替换。

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