[英]PhpMyadmin error #1064
okay so i have transferred my website % database over from an old computer which had now died and am trying to set it up on my own mac locally however I am running into a few issues. 好的,所以我已经从一台旧计算机转移了我的网站%数据库,该计算机现在已经死了,正在尝试在本地Mac上设置它,但是我遇到了一些问题。 As of now i have setup xampp and phpmyadmin however when i try to import my
.sql
database. 截至目前,我已经设置了xampp和phpmyadmin,但是当我尝试导入
.sql
数据库时。
I am getting an error: 我收到一个错误:
MySQL said: Documentation MySQL说:文档
1064 - You have an error in your SQL syntax;
1064-您的SQL语法有误; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TYPE=InnoDB AUTO_INCREMENT=3 AUTO_INCREMENT=3' at line 31
在第31行的'TYPE = InnoDB AUTO_INCREMENT = 3 AUTO_INCREMENT = 3'附近检查与您的MySQL服务器版本相对应的手册以使用正确的语法
-- version 2.8.0.1 -版本2.8.0.1
-- Host: custsql-ipg68.eigbox.net -- Generation Time: Aug 22, 2015 at 05:57 AM -- Server version: 5.5.44 -主机:custsql-ipg68.eigbox.net-生成时间:2015年8月22日,上午5:57-服务器版本:5.5.44
blake
blake
-- -
doctor
doctor
餐桌结构 CREATE TABLE `doctor` (
`D_id` int(11) NOT NULL AUTO_INCREMENT,
`D_name` varchar(145) NOT NULL,
`D_SSn` varchar(145) NOT NULL,
`Age` varchar(145) NOT NULL,
`Phone` varchar(145) NOT NULL,
`Address` varchar(145) NOT NULL,
`city` varchar(145) NOT NULL,
`state` varchar(145) NOT NULL,
`zip` varchar(145) NOT NULL,
`office` varchar(145) NOT NULL,
PRIMARY KEY (`D_id`)
) TYPE=InnoDB AUTO_INCREMENT=3 AUTO_INCREMENT=3 ;
-- -
doctor
doctor
数据 INSERT INTO `doctor` VALUES (1, 'David Jones', '123-64-2654', '48', '134-264-4567', '1234 st boulevard', 'Los Angeles', 'CA', '12345', '123456789');
-- -
patient
patient
CREATE TABLE `patient` (
`P_id` int(11) NOT NULL AUTO_INCREMENT,
`P_Name` varchar(145) NOT NULL,
`P_SSn` varchar(145) NOT NULL,
`BirthDate` varchar(145) NOT NULL,
`Phone` varchar(145) NOT NULL,
`Address` varchar(145) NOT NULL,
`city` varchar(145) NOT NULL,
`state` varchar(145) NOT NULL,
`zipcode` varchar(145) NOT NULL,
`P_Lname` varchar(145) NOT NULL,
`Gender` varchar(85) NOT NULL,
`Email` varchar(145) NOT NULL,
PRIMARY KEY (`P_id`)
) TYPE=InnoDB AUTO_INCREMENT=5 AUTO_INCREMENT=5 ;
-- -
patient
patient
表patient
数据 INSERT INTO `patient` VALUES (1, 'Mark', '624-54-1326', 'March-16-1856', '4172696000', '3801 South National Avenue', 'Springfield', 'MO', '65807', 'Alan', 'Male', 'test@domainname.com');
INSERT INTO `patient` VALUES (4, 'Blake', '00012', '01/09/2015', '093284203894', '66 evergreen street', 'sydey', 'qld', '4007', 'douglas', 'male', 'test@gmail.com.au');
To declare table type you should use ENGINE
instead of TYPE
. 要声明表类型,应使用
ENGINE
而不是TYPE
。 Type
is wrong syntax. Type
是错误的语法。
Change from 从
) TYPE=InnoDB AUTO_INCREMENT=3 AUTO_INCREMENT=3 ;
) TYPE=InnoDB AUTO_INCREMENT=5 AUTO_INCREMENT=5 ;
To 至
) ENGINE=InnoDB AUTO_INCREMENT=3 ;
) ENGINE=InnoDB AUTO_INCREMENT=5 ;
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