如何将datagridview值传递给另一种形式

Question

i am working with my c# windows aplication, in this application form named "patients" and other named "patientsDuplicatedName" which contain datagridview and load all Duplicated Patients Name (this and works fine,,) but i want when slsected Row get all values into form "patients" at run time (already open) without creating new form "Patients".. Below is the code I am referring to:

    public partial class frmPatientsNameDuplicated : Form
{
    PatientFiles frmPatientsFiles =new PatientFiles() ;
    public frmPatientsNameDuplicated()
    {
        InitializeComponent();
    }


   private void btnCancel_Click(object sender, EventArgs e)
   {
       this.Close();
   }

   private void btnOk_Click(object sender, EventArgs e)
   {

       frmPatientsFiles.txtFileNum.Text = this.dgvPatientsName.CurrentRow.Cells[0].Value.ToString();
       frmPatientsFiles.txtArbName.Text = this.dgvPatientsName.CurrentRow.Cells[1].Value.ToString();
       frmPatientsFiles.txtEngName.Text = this.dgvPatientsName.CurrentRow.Cells[2].Value.ToString();
       //frmPatientsFiles.show();//this line is creating new form and run 
       this.Close();

   }
}

sorry about my bad english & thanks in advance

Answer 1

The commented out line frmPatientsFiles.show() has a comment that says that the line is creating a new form. It is not. It is simply displaying a form that has been previously created on line PatientFiles frmPatientsFiles = new PatientFiles(); This appears to be creating the new form that you don't want. If you already have an existing form that you want to update, reference that form from your btnOk_Click event handler. To do this, you probably want to pass in a reference to the (existing) form to your class, either via the constructor or some other method/property. I hope I have understood your question correctly.

Answer 2

i found same issue here : Pass data to a existing form so my code become

public partial class frmPatientsNameDuplicated : Form
{
PatientFiles frmPatientsFiles = Application.OpenForms["PatientFiles"] as PatientFiles;
public frmPatientsNameDuplicated()
{
    InitializeComponent();
}
private void btnCancel_Click(object sender, EventArgs e)
{
   this.Close();
}

private void btnOk_Click(object sender, EventArgs e)
{
   frmPatientsFiles.txtFileNum.Text = this.dgvPatientsName.CurrentRow.Cells[0].Value.ToString();
   frmPatientsFiles.txtArbName.Text = this.dgvPatientsName.CurrentRow.Cells[1].Value.ToString();
   frmPatientsFiles.txtEngName.Text = this.dgvPatientsName.CurrentRow.Cells[2].Value.ToString();
   this.Close();
}
}