无法将函数参数分配给`Zsh`中的局部数组变量

Question

I just try to assign parameters of function as local array variable, I tried

$test_print(){local foo=( "${@:1}" ); echo $foo[*]}; test_print a b c

I got

test_print: bad pattern: foo=( a

But if I remove local keyword

$test_print(){foo=( "${@:1}" ); echo $foo[*]}; test_print a b c

It's work

a b c

What is a problem here? How can I keep my array to local variable?

Additional information

I tried this on bash shell, it's work well either as local or global variable.

Answer 1

In order to make the wanted assignment, you have to separate the declaration of foo and the assignment of the value into two command:

test_print(){local foo; foo=( "${@:1}" ); echo $foo[*]}; test_print a b c

---

According to the ZSH Manual local behaves like typeset :

**local [ {+|-}AEFHUahlprtux ] [ -LRZi [ n ]] [ name[=value] ] ...

Same as typeset, except that the options -g, and -f are not permitted. In this case the -x option does not force the use of -g, ie exported variables will be local to functions.

In the the paragraph on typeset it says:

Note that arrays currently cannot be assigned in typeset expressions, only scalars and integers.