如何检查数组是否包含字符串中的特定单词并获取它？

Question

I have a String[] and an input String :

String[] ArrayEx = new String[1];
String textInput = "a whole bunch of words"

What I want to do is check if the String contains a word present in the Array , like this.

Ex: textInput = "for example" and ArrayEx[0] = "example"

I know about this method:

Arrays.asList(yourArray).contains(yourValue)

but it checks the full String right? How do I check if the String contains a particular word present in the Array. Even if it is from an ArrayList I have no problem.

Also if yes, can I get that word from the String[] ? ie, in the above case get the String "example".

EDIT:

public void searchNearestPlace(String v2txt)
{
    Log.e("TAG", "Started");
    v2txt = v2txt.toLowerCase();
    String[] places = {"accounting, airport, amusement_park, aquarium, art_gallery, atm, bakery, bank, bar, beauty_salon, bicycle_store, book_store, bowling_alley, bus_station, cafe, campground, car_dealer, car_rental, car_repair, car_wash, casino, cemetery, church, city_hall, clothing_store, convenience_store, courthouse, dentist, department_store, doctor, electrician, electronics_store, embassy, establishment, finance, fire_station, florist, food, funeral_home, furniture_store, gas_station, general_contractor, grocery_or_supermarket, gym, hair_care, hardware_store, health, hindu_temple, home_goods_store, hospital, insurance_agency, jewelry_store, laundry, lawyer, library, liquor_store, local_government_office, locksmith, lodging, meal_delivery, meal_takeaway, mosque, movie_rental, movie_theater, moving_company, museum, night_club, painter, park, parking, pet_store, pharmacy, physiotherapist, place_of_worship, plumber, police, post_office, real_estate_agency, restaurant, roofing_contractor, rv_park, school, shoe_store, shopping_mall, spa, stadium, storage, store, subway_station, synagogue, taxi_stand, train_station, travel_agency, university, veterinary_care, zoo"};
    int index;
    for(int i = 0; i<= places.length - 1; i++)
    {
        Log.e("TAG","for");
        if(v2txt.contains(places[i]))
        {
            Log.e("TAG", "sensed?!");
            index = i;
    }
}

Say v2txt was "awesome airport" the sensed Log never does appear even though all other logs indicate it working

Edit2:

I am so embarrassed that I made such a dunder head mistake. My array is declared wrongly. There should be a " before every , . I am such a big idiot! Sorry will change it and let you know.

Answer 1

First of all it has nothing to do with android

Second the solution

boolean flag = false;
String textInput = "for example";
int index = 0;
String[] yourArray = {"ak", "example"};
for (int i = 0; i <= yourArray.length - 1; i++) {

    if (textInput.contains(yourArray[i])) {
        flag = true;
        index = i;

    }
}
if (flag) 
   System.out.println("found at index " + index);
else 
   System.out.println("not found ");

DEMO

EDIT :

Change your array to

String[] places = {"accounting", "airport", "amusement_park" };

and so on with other values with your array declaration it has one index.

Answer 2

you can split your string and get array of words

txArray = textInput.split(" ");

then for each element in txArray check if

Arrays.asList(ArrayEx).contains(txArray[i])

Answer 3

Try this;

Sting text2check = "Your Name":

for(int t = 0; t < array.length; t++)
{
if (text2check.equals(array[t])
// Process it Here
break;
}

Answer 4

This will take an String array, and search through all the strings looking for a specific char sequence found in a string. Also, native Android apps are programmed in the Java language. You might find it beneficial to read up more on Strings .

String [] stringArray = new String[5];
//populate your array
String inputText = "abc";
for(int i = 0; i < stringArray.length; i++){
    if(inputText.contains(stringArray[i]){
        //Do something
    }
}

Answer 5

txArray = "Hello I'm your String";
String[] splitStr = txArray.split(" ");
int i=0;
while(splitStr[i]){
if(Arrays.asList(ArrayEx).contains(txArray[i])){
System.out.println("FOUND");
}
i++;
}

Answer 6

You can use Java - Regular Expressions.

A regular expression is a special sequence of characters that helps you match or find other strings or sets of strings, using a specialized syntax held in a pattern. They can be used to search, edit, or manipulate text and data.

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Testing {

    public static void main(String[] args) {

        String textInput = "for example";
        String[] arrayEx = new String[1];
        arrayEx[0] = "example";

        Pattern p = Pattern.compile(arrayEx[0]);
        Matcher m = p.matcher(textInput);
        boolean matchedFoundStatus = false;
        while (m.find()) {
            matchedFoundStatus = true;
        }
        System.out.println("matchedFoundStatus:" + matchedFoundStatus);
    }

}

Answer 7

"How do I check if the String contains a particular word present in the Array?" is the same thing as Is there an element in the array, for which the input string contains this element

Java 8

String[] words = { "example", "hello world" };
String input = "a whole bunch of words";

Arrays.stream(words).anyMatch(input::contains);

(The matching words can also be extracted, if needed:)

Arrays.stream(words)
      .filter(input::contains)
      .toArray();

If you are stuck with Java 7, you will have to re-implement "anyMatch" and "filter" yourself:

Java 7

boolean anyMatch(String[] words, String input) {
    for(String s : words)
        if(input.contains(s))
            return true;
    return false;
}

List<String> filter(String[] words, String input) {
    List<String> matches = new ArrayList<>();
    for(String s : words)
        if(input.contains(s))
            matches.add(s);
    return matches;
}