如何使用Python在Linux中通过pid获取进程名称？

Question

I want to get the process name, given it's pid in python. Is there any direct method in python?

Answer 1

The psutil package makes this very easy.

import psutil

process = psutil.Process(pid)

process_name = process.name()

Answer 2

If you want to see the running process, you can just use os module to execute the ps unix command

import os
os.system("ps")

This will list the processes.

But if you want to get process name by ID, you can try ps -o cmd= <pid> So the python code will be

import os
def get_pname(id):
    return os.system("ps -o cmd= {}".format(id))
print(get_pname(1))

The better method is using subprocess and pipes.

import subprocess
def get_pname(id):
    p = subprocess.Popen(["ps -o cmd= {}".format(id)], stdout=subprocess.PIPE, shell=True)
    return str(p.communicate()[0])
name = get_pname(1)
print(name)

Answer 3

Command name (only the executable name):

from subprocess import PIPE, Popen

def get_cmd(pid)
    with Popen(f"ps -q {pid} -o comm=", shell=True, stdout=PIPE) as p:
        return p.communicate()[0]

Command with all its arguments as a string:

from subprocess import PIPE, Popen

def get_args(pid)
    with Popen(f"ps -q {pid} -o cmd=", shell=True, stdout=PIPE) as p:
        return p.communicate()[0]