我正在尝试使用“a.sort([1])”用整数和浮点数对python中的列表进行排序，但它不起作用

Question

I am trying to sort a list in python with integers and a float using "a.sort([1])" (I am sorting it from the second element of the list) but it keeps on saying "TypeError: must use keyword argument for key function". What should I do? Also my list looks like this: ["bob","2","6","8","5.3333333333333"]

Answer 1

Paul's answer does a nice job of explaining how to use sort correctly.

I want to point out, however, that sorting strings of numbers is not the same as sorting numeric values (ints and floats etc.). Sorting by strings will use character collating sequence to determine the order, eg

>>> l = ['100','1','2','99']
>>> sorted(l)
['1', '100', '2', '99']

but this is probably not what you want; 100 is greater than 2 and so should appear further back in the list than 2. You can sort by numeric value, but retain strings for the list items using the key parameter to sort() :

>>> sorted(l, key=lambda x: float(x))
['1', '2', '99', '100']

Here the key is a lambda function that converts its argument to a float. The sort() routine will use the converted value as the sort key, not the string value that is actually contained in the list.

To sort from the second list item on, do this:

>>> a = ["bob", "2", "6", "8", "5.3333333333333"]
>>> a[1:] = sorted(a[1:], key=lambda x: float(x))
>>> a
['bob', '2', '5.3333333333333', '6', '8']

Answer 2

try to do "a.sort()". it will sort your list. sort cant get 1 as argument. read more here: http://www.tutorialspoint.com/python/list_sort.htm

if you trying to sort every element except the first one try to do:

a[1:] = sorted(a[1:])