使用Declytype推导类型时删除CV限定词

Question

I have a constant declared as following: 我有一个常量声明如下：

const auto val = someFun();

Now I want another variable with same type of 'val' but without the constant specification. 现在，我想要另一个具有相同类型“ val”但没有常量说明的变量。

decltype(val) nonConstVal = someOtherFun();
// Modify nonConstVal, this is error when using decltype

Currently decltype keeps the constness. 当前，decltype保持常数。 How to strip it? 如何剥离？

Answer 1

From <type_traits> 来自<type_traits>

You may use in C++14: 您可以在C ++ 14中使用：

std::remove_cv_t<decltype(val)> nonConstVal = someOtherFun();

or in C++11 或在C ++ 11中

std::remove_cv<decltype(val)>::type nonConstVal = someOtherFun();