[英]print all SubClass in a SuperClass and all SuperClass in a SubClass
I want in SuperClass print all subClasses and in a subClasses print all SuperClasses: 我想要在SuperClass中打印所有子类,并在子类中打印所有的SuperClass:
class SuperClass():
def Print(self):
print('my sub classes are : ')
#print all childs
class Sub1(SuperClass,...):
def Print(self):
print('My parents are :')
#print all SuperClasses
class Sub2(SuperClass,...):
def Print(self):
print('My parents are :')
#print all SuperClasses
SuperClass has Print that print all classes that inherit from , and Sub has Print method that print all his SuperClasses . SuperClass具有Print可以打印从其继承的所有类,而Sub具有Print方法可以打印其所有SuperClasses。 how do that ?
怎么办?
Python classes have three attributes that help here: Python类具有三个属性,可在此处提供帮助:
class.__subclasses__()
; class.__subclasses__()
; a method that returns all subclasses of the class. 返回该类的所有子类的方法。
class.__bases__
, a tuple of the direct parent classes of the current class. class.__bases__
,当前类的直接父类的元组。
class.__mro__
, a tuple with all classes in the current class hierarchy. class.__mro__
,具有当前类层次结构中所有类的元组。 Find the current class object in that tuple and everything following is a parent class, directly or indirectly. 在该元组中找到当前的类对象,其后的所有对象都是直接或间接的父类。
Using these that gives: 使用这些可以得到:
class SuperClass(object):
def print(self):
print('my sub classes are:', ', '.join([
cls.__name__ for cls in type(self).__subclasses__()]))
class Sub1(SuperClass):
def print(self):
print('My direct parents are:', ', '.join([
cls.__name__ for cls in type(self).__bases__]))
all_parents = type(self).__mro__
all_parents = all_parents[all_parents.index(Sub1) + 1:]
print('All my parents are:', ', '.join([
cls.__name__ for cls in all_parents]))
Demo: 演示:
>>> SuperClass().print()
my sub classes are: Sub1
>>> Sub1().print()
My direct parents are: SuperClass
All my parents are: SuperClass, object
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.