[英]c# LINQ get Attribute value from XElement
I have the below XML in a data definitions file: 我在数据定义文件中包含以下XML:
<PQTemplate documentID="CSTrlsEN" documentType="TransList" templateID="001"
templateType="Customer Copy"
templateName="C:\CPS\_templates\Mini-Statements\CSTrlsEN.doc">
<field pos="5" name="YPTME" descr="Time" />
<field pos="6" name="YPDTE" descr="Action Date" />
<field pos="7" name="YPBRNO" descr="Branch Number" />
<field pos="8" name="YPBNA" descr="Branch Name" />
<field pos="9" name="YPTID" descr="Teller ID" />
<field pos="10" name="YPISN" descr="Teller Sequence" />
<field pos="11" name="YPREF" descr="Customer Reference" />
<field pos="12" name="YPCUS" descr="Customer Name" />
<field pos="13" name="YPEAN" descr="Account Number" />
<field pos="14" name="YPATY" descr="Account Type" />
<field pos="15" name="YPCUR" descr="Currency" />
<field pos="16" name="YPBAL" descr="Available Balance" />
I get that specific XElement using LINQ, extracting it from an XML file that contains several PQTemplate
elements by using the below LINQ Expression: 我使用LINQ获得了特定的XElement,并使用下面的LINQ表达式从包含几个
PQTemplate
元素的XML文件中提取了它:
var mapInfo = from nm in XElement.Elements("PQTemplate")
where (string)nm.Attribute("documentID") == sRequests[0].Split('\t')[0]
select nm;
Now I need to get the value of the attribute documentType so I tried the below LINQ Expression: 现在,我需要获取属性documentType的值,因此尝试了以下LINQ表达式:
var repName = from d in mapInfo.Attributes("documentType")
select d.Value;
reportName = repName.ToString();
Unfortunately although I can see the value TransList is part of the reportName element, I have had no luck trying to retrieve it. 不幸的是,尽管我看到TransList值是reportName元素的一部分,但是我没有运气尝试检索它。
Here is an image showing it in VS 2013: 这是在VS 2013中显示的图片:
so how can I get the documentType
attribute in the element? 那么如何获取元素中的
documentType
属性呢?
That's because repName
will return an IEnumerable<string>
for all the mapInfo
. 这是因为
repName
将返回IEnumerable<string>
所有mapInfo
。
IEnumerable<string> repName = from d in mapInfo.Attributes("documentType")
select d.Value;
So either use a foreach
loop if you suspect you may get more values or use First
to get first attribute like this:- 因此,如果怀疑可能会得到更多的值,请使用
foreach
循环,或者使用First
来获取第一个属性,例如:
string reportName = mapInfo.First().Attribute("documentType").Value;
Linq queries return collections. Linq查询返回集合。 Do
for each
over repName
or for each
repName
或
repName.First().ToString()
if that is all you need. 如果这就是您所需要的。
Your solution depends on how many elements DocumentType
exist in your XML. 您的解决方案取决于XML中存在
DocumentType
元素数量。 If it´s only one (what I suppose) you may use repName.First().ToString()
. 如果只有一个(我想),则可以使用
repName.First().ToString()
。
If the attribute may occure more than once you should use a loop instead: 如果该属性可能出现多次,则应改为使用循环:
var result = new List<string>();
foreach(var a in (from d in mapInfo.Attributes("documentType") select d.Value)
result.Add(a.ToString());
Or even shorter: 甚至更短:
result = mapInfo.Attributes("documentType").Select(x => x.Value.ToString());
Which will return an enumeration. 这将返回一个枚举。
Change 更改
var mapInfo = from nm in XElement.Elements("PQTemplate")
where (string)nm.Attribute("documentID") == sRequests[0].Split('\t')[0]
select nm;
to 至
var mapInfo = from nm in XElement.Elements("PQTemplate")
where (string)nm.Attribute("documentID") == sRequests[0].Split('\t')[0]
select nm.Attribute("documentType").Value;
then mapInfo.First()
will give you the value you want. 然后
mapInfo.First()
将为您提供所需的值。
To get a single value out of a LINQ query you have to call for example First
or FirstOrDefault
. 要从LINQ查询中获取单个值,您必须调用例如
First
或FirstOrDefault
。 If you call FirstOrDefault
it won't throw an exception if the query returns no matches. 如果调用
FirstOrDefault
,则在查询未返回任何匹配FirstOrDefault
它不会引发异常。
string repName = doc.Elements("PQTemplate")
.Where(e => (string)a.Attribute("documentID") == sRequests[0].Split('\t')[0])
.Select(e => (string)e.Attribute("documentType"))
.FirstOrDefault();
Also, you don't need to call ToString()
on XAttribute.Value
as it's already a string
. 另外,您不需要在
XAttribute.Value
上调用ToString()
,因为它已经是string
。
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