需要获得最接近的最小值和最大值

Question

Here I have a query regarding the getting nearest minimum and maximum values. I have a range :

2.43 - 3.57 lakhs

Now i need to get the nearest values to minimum and maximum values.

I have tried with this query didn't get the desired result.

$othsimlar_prices = "select ABS(exshowroom - ".$price_query['minprice'].") as minprice,
                            ABS(exshowroom - ".$price_query['maxprice'].") as maxprice,
                            make,
                            model 
                    from ncp_variant_cache 
                    order by maxprice";

Answer 1

why you don't use 'where' and 'and' ?

$othsimlar_prices = "select * 
                    from ncp_variant_cache
where minprice=ABS(exshowroom - ".$price_query['minprice'].")
and maxprice=ABS(exshowroom - ".$price_query['maxprice'].")
                    order by maxprice"

;

OR if you have only one column with price you could just:

select * from your_table where price between interval1 and interval2

Answer 2

Crude way to get it:-

SELECT exshowroom ,
        make,
        model,
        0 AS range_diff
FROM ncp_variant_cache 
WHERE exshowroom BETWEEN ".$price_query['minprice']." AND ".$price_query['maxprice']."
UNION
SELECT exshowroom ,
        make,
        model,
        ABS(exshowroom - ".$price_query['maxprice'].") AS range_diff
FROM ncp_variant_cache 
WHERE exshowroom > ".$price_query['maxprice']."
UNION
SELECT exshowroom ,
        make,
        model,
        ABS(".$price_query['minprice']." - exshowroom) AS range_diff
FROM ncp_variant_cache 
WHERE exshowroom < ".$price_query['minprice']."
ORDER BY range_diff
LIMIT 1

This uses 3 unioned queries. The first gets any record that is within the price range, the 2nd gets the record closest to the max pricewhile the 3rd gets the record closest to the min price. The result is ordered by the difference (with ones within the range having the difference set to 0) limited to 1 row back.