在javascript中使用正则表达式替换字符的奇数出现

Question

I have a string which contains '#'. I want to replace occurrence of only odd '#' with something else.

For eg for below string

This is my string # This is my string # This is my string # This is my string #

output should be

This is my string # This is my string '' This is my string # This is my string ''

Note : considering occurrence starts with 0

Answer 1

([^#]*#[^#]*)#

You can use this.Replace by $1" .See demo.

https://regex101.com/r/cT0hV4/9

var re = /([^#]*#[^#]*)#/gm; 
var str = 'This is my string # This is my string # This is my string # This is my string #';
var subst = '$1"'; 

var result = str.replace(re, subst);

Answer 2

Try using this regex:

#(.*?(?:#|$))

Regex Demo

EDIT:

var reg = /#(.*?(?:#|$))/; 
var message = 'This is my string # This is my string # This is my string # This is my string #';
var substitue = '$1"'; 

var result = message.replace(reg, substitue);
alert(result);

JSFIDDLE DEMO

Answer 3

您可以使用以下正则表达式来执行此操作

str.replace(/(#.*?)#/g, '$1"')