将 char 数组转换为 char 常量 (c)

Question

so im trying to figure out how to change an array to a constant but i keep getting a this error

warning: incompatible pointer types passing
'char *[3]' to parameter of type 'char *' [-Wincompatible-pointer-types]
    strcpy(input, inputcon);
           ^~~~~`

here is my code

int main(void) {

    char *input[3];
    int yn = 0;
    char *no = "no";
    char *inputcon = NULL;
    do {
        printf("This is the game.\nDo you want to play again?\nType y/n: ");
        scanf("%s",*input);
        strcpy(input, inputcon);
        yn = strcmp(inputcon, no);
    } while (yn == 1);
}

Answer 1

First of all,

 char *input[3];

defines an array of char pointers, which you don't want here. A simple char array will do the job. Change it to

char input[4] = {0};   //assuming you want yes to be stored, 
                       // reserve space for terminating null

Secondly,

 scanf("%s",*input);

should be

scanf("%3s",input); //limit the input as per the buffer length

Third,

strcpy(input, inputcon);

is entirely unnecessary, Remove it.

Then, you need to replace

yn = strcmp(inputcon, no);

with

yn = strcmp(input, no);

That said, you should change the prompt to ask user to input yes or no .