[英]Create a table with unique values from another table
I am using MS SQL Server Management Studio. 我正在使用MS SQL Server Management Studio。 I have table -
我有桌子 -
+--------+----------+
| Num_ID | Alpha_ID |
+--------+----------+
| 1 | A |
| 1 | B |
| 1 | C |
| 2 | B |
| 2 | C |
| 3 | A |
| 4 | C |
| 5 | A |
| 5 | B |
+--------+----------+
I want to create another table with 2 columns from this table so that column_1 gives Unique values in Num_ID (ie 1,2,3,4 and so on) and column_2 gives Unique values in Alpha_ID (A, B, C and so on). 我想创建另一个包含此表中2列的表,以便column_1在Num_ID中给出唯一值(即1,2,3,4等),column_2在Alpha_ID中给出唯一值(A,B,C等) 。
But if an alphabet has already occurred, it should not occur again. 但是如果已经发生了字母表,则不应该再次出现。 So the output will be something like this -
所以输出将是这样的 -
Col_1 Col_2
================
1 - A
----------------
2 - B
----------------
3 - NULL (as A has been chosen by 1, it cannot occur next to 3)
----------------
4 - C
----------------
5 - NULL (both 5 A and 5 B cannot be chosen as A and B were picked up by 1 and 2)
----------------
Hope that makes sense. 希望有道理。 I would like to clarify that the IDs in the input table are not numerical as I have shown, but both Num_ID and Alpha_ID are complex strings.
我想澄清一下,输入表中的ID不是我所示的数字,但Num_ID和Alpha_ID都是复杂的字符串。 I have simplified them to 1,2,3,... and A, B, C .... for the purpose of this question
为了这个问题的目的,我把它们简化为1,2,3,......和A,B,C ....
I don't think this could be done without a cursor. 我不认为没有光标就可以做到这一点。 I added few more rows to your sample data to test how it works with other cases.
我在您的示例数据中添加了更多行,以测试它与其他案例的工作方式。
The logic is straight-forward. 逻辑是直截了当的。 At first get a list of all distinct values of
Num_ID
. 首先获取
Num_ID
的所有不同值的Num_ID
。 Then loop through them and with each iteration add one row to the destination table. 然后遍历它们并在每次迭代时向目标表添加一行。 To determine the
Alpha_ID
value to add I'll use EXCEPT
operator that takes all available Alpha_ID
values for the current Num_ID
from the source table and removes from them all values that have been used before. 要确定要添加的
Alpha_ID
值,我将使用EXCEPT
运算符,该运算符从源表中获取当前Num_ID
所有可用Alpha_ID
值,并Num_ID
删除之前使用过的所有值。
It is possible to write that INSERT
without using explicit variable @CurrAlphaID
, but it looks a bit cleaner with variable. 可以在不使用显式变量
@CurrAlphaID
情况下编写INSERT
,但它看起来有点变得干净。
Here is SQL Fiddle . 这是SQL小提琴 。
DECLARE @TSrc TABLE (Num_ID varchar(10), Alpha_ID varchar(10));
INSERT INTO @TSrc (Num_ID, Alpha_ID) VALUES
('1', 'A'),
('1', 'B'),
('1', 'C'),
('2', 'B'),
('2', 'C'),
('3', 'A'),
('3', 'C'),
('4', 'A'),
('4', 'C'),
('5', 'A'),
('5', 'B'),
('5', 'C'),
('6', 'D'),
('6', 'E');
DECLARE @TDst TABLE (Num_ID varchar(10), Alpha_ID varchar(10));
DECLARE @CurrNumID varchar(10);
DECLARE @CurrAlphaID varchar(10);
DECLARE @iFS int;
DECLARE @VarCursor CURSOR;
SET @VarCursor = CURSOR FAST_FORWARD
FOR
SELECT DISTINCT Num_ID
FROM @TSrc
ORDER BY Num_ID;
OPEN @VarCursor;
FETCH NEXT FROM @VarCursor INTO @CurrNumID;
SET @iFS = @@FETCH_STATUS;
WHILE @iFS = 0
BEGIN
SET @CurrAlphaID =
(
SELECT TOP(1) Diff.Alpha_ID
FROM
(
SELECT Src.Alpha_ID
FROM @TSrc AS Src
WHERE Src.Num_ID = @CurrNumID
EXCEPT
SELECT Dst.Alpha_ID
FROM @TDst AS Dst
) AS Diff
ORDER BY Diff.Alpha_ID
);
INSERT INTO @TDst (Num_ID, Alpha_ID)
VALUES (@CurrNumID, @CurrAlphaID);
FETCH NEXT FROM @VarCursor INTO @CurrNumID;
SET @iFS = @@FETCH_STATUS;
END;
CLOSE @VarCursor;
DEALLOCATE @VarCursor;
SELECT * FROM @TDst;
Result 结果
Num_ID Alpha_ID
1 A
2 B
3 C
4 NULL
5 NULL
6 D
Having index on (Num_ID, Alpha_ID)
on the source table would help. 在源表上具有索引
(Num_ID, Alpha_ID)
会有所帮助。 Having index on (Alpha_ID)
on the destination table would help as well. 在目标表上具有索引
(Alpha_ID)
也会有所帮助。
I think I've made something not through a recursion (cursor or a while) 我想我已经做了一些不是通过递归(光标或一段时间)
First, I created a table with rows. 首先,我创建了一个包含行的表。
create table #tmptest
(
Num_ID int
, Alpha_ID varchar(50)
)
insert into #tmptest (Num_ID, Alpha_ID) values
(1,'A'),
(1,'B'),
(1,'C'),
(2,'B'),
(2,'C'),
(3,'A'),
(4,'C'),
(5,'A'),
(5,'B')
// this one, with row column
SELECT
ROW_NUMBER() OVER (PARTITION BY Num_ID ORDER BY Num_ID ASC) as row
, *
INTO #tmp_withrow
FROM #tmptest
and these were the results 这些都是结果
Lastly, I made an inner query (could possibly be a left join or better). 最后,我做了一个内部查询(可能是左连接或更好)。
SELECT DISTINCT
Num_ID
, (
SELECT
TOP 1
Alpha_ID
FROM #tmp_withrow in1
WHERE
in1.Num_ID = t.Num_ID
AND in1.Alpha_ID NOT IN (
SELECT
Alpha_ID
FROM #tmp_withrow in2
WHERE
in2.Num_ID < in1.Num_ID
AND in2.row = 1
)
ORDER BY in1.Num_ID ASC
) AS [NonRepeatingAlpha]
from #tmptest t
and these were the results 这些都是结果
Note : I created a flag ( row
) which will allow you to query all less than the ID's you're in ( in2.Num_ID < in1.Num_ID
) then find out what letters where already used ( in2.row = 1
) and then select / avoid all letters that has already been used from the other Num_ID ( 注意:我创建了一个标志(
row
),它允许您查询所有小于您所在的ID( in2.Num_ID < in1.Num_ID
),然后找出已经使用过的字母( in2.row = 1
)然后选择/避免已从其他Num_ID使用的所有字母(
WHERE in1.Num_ID = t.Num_ID
AND in1.Alpha_ID NOT IN (
SELECT
Alpha_ID
FROM #tmp_withrow in2
WHERE
in2.Num_ID < in1.Num_ID
AND in2.row = 1
) )
I hope this helps. 我希望这有帮助。 Thanks!
谢谢!
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