我如何在不使用数组的情况下获取foreach之外的值？

Question

I want to get calleridnum without using array . Is this possible? or is there other way to do this ?

I have this code :

$participants = [
    [   'calleridnum' => 1,
        'test' => 'yay' 
    ],
    [   'calleridnum' => 2,
        'test' => 'yay' 
    ],
     [   'calleridnum' => 3,
        'test' => 'yay' 
    ]
];
$conferance_participants = [
    [   'uid' => 1,
        'test' => 'yay2',
        'dit' => 'deze'
    ],
    [  'uid' => 2,
        'test' => 'test',
        'dit' => 'wew'
    ]
];

foreach ($participants as $key=>$p) {
    foreach ($conferance_participants as $key=>$cp) {

        if ($p['calleridnum'] == $cp['uid']) {
                $calleridnum[]  =   $p['calleridnum'];

        } 

    } 
}

print_r( $calleridnum );

My output is:

Array ( [0] => 1 [1] => 2 )

but I want the output to be like this

1,2

Answer 1

Try this: Implode your array to be converted into string.

  $calleridnum= [];

  foreach ($participants as $key=>$p) {
    foreach ($conferance_participants as $key=>$cp) {

     if ($p['calleridnum'] == $cp['uid']) {
            $calleridnum[]  =   $p['calleridnum'];

     } 

    } 
 }

$result = implode(',', $calleridnum);
echo $result;

Answer 2

在foreach loop外使用implode()

 echo $str = implode (",", $calleridnum);

Answer 3

I'll simply use array_intersect , array_column along with implode as

echo implode(',', array_intersect(array_column($conferance_participants,'uid'), array_column($participants,'calleridnum')));

Demo