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如何比较两个XML文档?

[英]How can I compare 2 XML Documents?

I have two documents both are similar but I need to find an elegant and efficient way to compare the two files and return the values in Doc #1 that don't exist in Doc #2. 我有两个文档都相似,但是我需要找到一种优雅而有效的方式来比较两个文件并返回Doc#1中不存在Doc#2中的值。

XML Doc #1 XML文件#1

      <ids>
        <id>1</id>
        <id>2</id>
        <id>5</id>
        <id>6</id>
        <id>7</id>
        <id>8</id>
        <id>9</id>
       </ids>
    </ids>

XML Doc #2 XML文件#2

  <ids>
    <id>1</id>
    <id>2</id>
    <id>7</id>
    <id>8</id>
    <id>9</id>
  </ids>

I was thinking about using linq if I could join these two documents on the id field. 我在考虑使用linq是否可以在id字段上加入这两个文档。 Is there a better way? 有没有更好的办法? I'm looking to return id #s 5 and 6. 我希望返回ID 5和6。

Here is a sample that I know works, I only tried it out with small files (File1.xml had 20 items, File2.xml 8 items). 这是一个我知道有效的示例,我仅使用小文件(File1.xml有20个项目,File2.xml有8个项目)进行了尝试。

XDocument file1Doc = XDocument.Load("File1.xml");
XDocument file2Doc = XDocument.Load("File2.xml");

IEnumerable<string> file1Elements = from d in file1Doc.Descendants("Id")
                                    select d.Value;

IEnumerable<string> file2Elements = from d in file2Doc.Descendants("Id")
                                    select d.Value;

var difference = file1Elements.Except(file2Elements);

Alternatively, and likely more inline with what you seek is: 另外,可能更符合您的需求的是:

XDocument file1Doc = XDocument.Load("File1.xml");
XDocument file2Doc = XDocument.Load("File2.xml");

IEnumerable<string> file2Elements = from d in file2Doc.Descendants("Id")
                                    select d.Value;

var x = from include in file1Doc.Descendants("Id")
        where file2Elements.Contains(include.Value) != true
        select include;

You might also find some help looking at 101 LINQ Samples on MSDN . 您还可以在MSDN上查看101 LINQ示例获得帮助。

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