[英]Socket.io return value
I have server.js 我有server.js
io.sockets.on('connection', function(socket){
socket.on('duplicite', function(name){
for(var i=0; i<clients.length; i++) {
if(clients[i] == name){
io.to(socket.id).emit('duplicite', true);
}else{
io.to(socket.id).emit('duplicite', false);
}
}
});
});
and client.html 和client.html
socket.emit('duplicite', name);
socket.on('duplicite', function(ret){
if(ret){
alert("non-OK");
}else
{alert("OK");}
});
I want to find duplicites. 我想找到杜普利特人。 When first socket connected with name "name" everything is OK, and I get alert with "OK". 当第一个使用名称“ name”的套接字连接时,一切正常,并且我收到“ OK”的警报。 But when second socket connected with name "name" i get alert with "non-OK" and "OK" too. 但是,当第二个套接字以名称“ name”连接时,我也会收到“ non-OK”和“ OK”的警报。
Try using an object instead, it's easier to check for existing names using the square-bracket notation: 尝试使用一个对象,使用方括号符号更容易检查现有名称:
/*
could use {} but we'll use Object.create(null) to create a basic
dictionary object, so we don't have to use hasOwnProperty()
*/
var clients = Object.create(null);
io.sockets.on('connection', function(socket){
socket.on('duplicite', function(name){
if (!clients[name]) {
socket.emit('duplicite', false);
clients[name] = null; // no duplicate so put name onto object
}
else socket.emit('duplicite', true);
});
});
Regarding your original code using an array, you should put a break;
关于使用数组的原始代码,应该break;
in your first if condition, so it doesn't keep sending messages. 在您的第一个if条件中,因此它不会一直发送消息。
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