带有负字节的java中的XOR

Question

byte b = -0b0101^-0b0100;
System.out.println("Outputs "+b);
//Outputs 7

Why does this output 7 ( 0b111 ) when I was expecting 1 ( 0b001 )?

Answer 1

Negative numbers are calculated according to "two's complement" arithmetic.

-0b0101 = NOT(0000 0101) + 1 = 1111 1010 + 1 = 1111 1011
-0b0100 = NOT(0000 0100) + 1 = 1111 1011 + 1 = 1111 1100

If you XOR these you get:

0000 0111 = 7

Answer 2

For presenting negative numbers in binary we use "Two's complement"

This is how you get negative binary numbers in java, check this link: How are integers internally represented at a bit level in Java?

Then you get: -5 in binary is 11111011 -4 in binary is 11111100 -------- 00000111 = which is 7. That is why output is 7, hope it helps.