[英]How to update data in json using jquery and ajax
I am trying to update my json if uid = 0090000219 i want to change my "secret"
我要更新我的json,如果uid = 0090000219我想更改我的
"secret"
i have this json: 我有这个json:
[
{
"id":23,
"uid":"0090000219",
"cid":"0090000013",
"extension":"201",
"secret":"Myojyo42_f",
"leader":true,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-02 12:49:12",
"updated_at":"2015-09-02 12:49:12"
},
{
"id":24,
"uid":"0090000221",
"cid":"0090000013",
"extension":"203",
"secret":"Myojyo42_f",
"leader":false,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-02 12:49:12",
"updated_at":"2015-09-02 12:49:12"
},
{
"id":25,
"uid":"0090000220",
"cid":"0090000013",
"extension":"202",
"secret":"Myojyo42_f",
"leader":false,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-08 07:40:04",
"updated_at":"2015-09-08 07:40:04"
},
{
"id":26,
"uid":"0090000223",
"cid":"0090000013",
"extension":"205",
"secret":"Myojyo42_f",
"leader":false,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-08 07:40:04",
"updated_at":"2015-09-08 07:40:04"
}
]
this is my code but it doesnt update: 这是我的代码,但不会更新:
<script src="//code.jquery.com/jquery-1.11.3.min.js"></script>
<script type="text/javascript">
var conf_url = "https://192.168.236.33/confbridge_participants/conference_participants.json?cid=0090000013";
getParticipant(conf_url, function(data){
for (var i=0; i<data.length; i++) {
if (data[i].uid == 0090000219) {
data[i].secret = "Secret";
break;
}
}
alert("New secret: " + data[2].secret);
});
function getParticipant(conf_uri, handleData) {
$.ajax({
type: "GET",
url: conf_uri,
dataType: "jsonp",
jsonpCallback: 'callback',
contentType: "application/javascript",
success: function(data) {
handleData(data);
// console.log(data);
}
});
}
</script>
You're looking at the wrong value to check whether or not it succeeded. 您正在查看错误的值以检查它是否成功。 You need to check the first object in the array, not the 3rd...
您需要检查数组中的第一个对象,而不是第三个对象。
alert("New secret: " + data[0].secret);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.