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Scala编译错误:“没有可用的隐式视图”和“分散的隐式扩展”

[英]Scala compile errors: “No implicit view available” and “diverging implicit expansion”

 def MyFun(result: ListBuffer[(String, DateTime, List[(String, Int)])]):
 String = {
 val json =
  (result.map {
    item => (
      ("subject" -> item._1) ~
        ("time" -> item._2) ~
        ("student" -> item._3.map {
          student_description=> (
            ("name" -> lb_result._1) ~
              ("age" -> lb_result._2) 
            )
        })
      )
    }
    )
    val resultFormat = compact(render(json))
    resultFormat  
}

error 1: No implicit view available from org.joda.time.DateTime => org.json4s.JsonAST.JValue.("subject" -> item._1) ~ 错误1:从org.joda.time.DateTime => org.json4s.JsonAST.JValue。(“主题”-> item._1)中没有隐式视图可用〜

error 2: diverging implicit expansion for type Nothing => org.json4s.JsonAST.JValue starting with method seq2jvalue in trait JsonDSL val resultFormat = compact(render(json)) 错误2:类型Nothing => org.json4s.JsonAST.JValue的隐式扩展在特征JsonDSL val中的方法seq2jvalue开始发散val resultFormat = compact(render(json))

I hinted at json4s-ext for joda-time support, but only importing this submodule won't solve your problem. 我向json4s-ext暗示了对joda-time的支持,但是仅导入此子模块并不能解决您的问题。

JsonDSL is used to create JValues and serializers are only used to turn JValues into JSON and vise versa (serialization and deserialization). JsonDSL用于创建JValues而序列化程序仅用于将JValues转换为JSON,反之亦然(序列化和反序列化)。

If we try to create a simpler json object with a DateTime : 如果我们尝试使用DateTime创建一个更简单的json对象:

val jvalue = ("subj" -> "foo") ~ ("time" -> DateTime.now)

We get the same error : 我们得到同样的错误:

error: No implicit view available from org.joda.time.DateTime => org.json4s.JsonAST.JValue.

Like I said, the serializers for DateTime from json4s-ext are not used when we use JsonDSL to create JValues . 就像我说的那样,当我们使用JsonDSL创建JValues时,不使用json4s-extDateTime的序列化JValues

You could create an implicit function DateTime => JValue or do something like DateTime.now.getMillis or DateTime.now.toString to create respectively a JInt or a JString , but why would we reinvent the wheel if joda time serializers already exist ? 您可以创建一个隐式函数DateTime => JValue或执行类似DateTime.now.getMillisDateTime.now.toString来分别创建JIntJString ,但是如果已经存在joda时间序列化JString ,为什么还要重新发明轮子呢?

We can introduce some case classes to hold the data in result and then json4s can serialize them for us : 我们可以引入一些case类来保存result的数据,然后json4s可以为我们序列化它们:

import scala.collection.mutable.ListBuffer

import com.github.nscala_time.time.Imports._

import org.json4s._
import org.json4s.JsonDSL._
import org.json4s.native.JsonMethods._
import org.json4s.native.Serialization
import org.json4s.native.Serialization.{read, write}

implicit val formats = 
  Serialization.formats(NoTypeHints) ++ org.json4s.ext.JodaTimeSerializers.all

case class Lesson(subject: String, time: org.joda.time.DateTime, students: List[Student])
case class Student(name: String, age: Int)

val result = ListBuffer(("subj", DateTime.now, ("Alice", 20) :: Nil))
val lessons =  result.map { case (subj, time, students) => 
  Lesson(subj, time, students.map(Student.tupled))
}

write(lessons)
// String = [{"subject":"subj","time":"2015-09-09T11:22:59.762Z","students":[{"name":"Alice","age":20}]}]

Note that you still need to add json4s-ext like Andreas Neumann explained. 请注意,您仍然需要像Andreas Neumann所解释的那样添加json4s-ext

As Peter Neyens allready said for serializing org.joda.time.DateTime you ned the ext package 正如Peter Neyens早就说过要序列化org.joda.time.DateTime您已经设置了ext包。

https://github.com/json4s/json4s#extras https://github.com/json4s/json4s#extras

So add this dependency to you build.sbt 因此,将此依赖项添加到您的build.sbt

libraryDependencies += "org.json4s" %% "json4s-ext" % "3.2.11"

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