定义引用其他别名的别名

Question

I'd need to be able to define an alias in a Debian shell that includes other aliases, for a project I'm currently working on.

Let's look at a code example to make things more clear.

1. alias foo=foo
2. alias bar=bar

If I run type foo it returns foo is aliased to 'foo' , and type bar returns bar is aliased to 'bar' . Up to here all fine. Now, where I'm having the problem.

3. alias foobar=$foo$bar

Doesn't work. type foobar returns foobar is aliased to '' .

I've tried alias foobar=${foo}${bar} and it doesn't work either.

Once I get this working, in the final version I actually need some text in between the two aliases, imagine something like: alias fooandbar=${foo}and${bar} .

Can anyone help please?

Answer 1

To reuse alias in another alias use:

foobar='foo;bar'

However I would suggest you to consider using shell function to get better control over this.

Answer 2

Following @anubhava's sage advice:

foo() { echo foo; }
bar() { echo bar; }
foobar() { echo "$(foo)$(bar)"; }
fooandbar() { echo "$(foo)and$(bar)"; }

Spaces and semicolons inside {} are required there.

Answer 3

I used this in csh and it worked for me :

alias new_alias 'vi old_alias'

Answer 4

Here is an example of alias that i'm using

#clear
alias cls='clear; ls'
alias ccls='cd; cls' # used alias cls