Android应用程序可在模拟器上正常运行，但在真实设备上崩溃

Question

I'm developing an android application which use MySQL database and json, it works on emulator correctly but when im launching it on my device (Galaxy S5) I'm facing a force close Here is my request to server and get json objects:

    btnFaalSazi.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {

            String validatePhoneNumber = phoneNumber.getText().toString();
            if (validatePhoneNumber.matches("^(?:0\\d{10}|9\\d{9})$")) {

                txtError.setText("");
                structUsers.register_number = phoneNumber.getText().toString();
                String phone = structUsers.register_number;

                Log.i("LOG", phone);
                Log.i("LOG", "HELOOOOOO");

                final ArrayList<NameValuePair> params = new ArrayList<NameValuePair>();
                params.add(new BasicNameValuePair("register_number", phone));

                String result = Webservice.readUrl("http://192.168.10.110:2233/api/register", params);

                if (result != null) {
                    try {
                        G.users.clear();
                        JSONObject object = new JSONObject(result);
                        String status = object.optString("status");
                        String code = object.optString("code");
                        String message = object.optString("message");

                        Log.i("LOG", "status hast " + status);
                        Log.i("LOG", "code hast  " + code);
                        Log.i("LOG", "mesage hast  " + message);

                        if (status != null && code != null) {
                            if (Integer.parseInt(status) == -1) {
                                Intent intent = new Intent(ActivityRegisterNumber.this, ActivityRegisterCode.class);
                                intent.putExtra("REGISTERNUMBER", structUsers.register_number);
                                ActivityRegisterNumber.this.startActivity(intent);
                            }
                        }

                        if (status != null && message != null) {
                            if (Integer.parseInt(status) == 100) {
                                Toast.makeText(getApplicationContext(), message, Toast.LENGTH_LONG).show();
                                Log.i("LOG", "after error 100");
                            } else if (Integer.parseInt(status) == 101) {
                                Toast.makeText(getApplicationContext(), message, Toast.LENGTH_LONG).show();
                                Log.i("LOG", "after error 101");
                            } else if (Integer.parseInt(status) == 102) {
                                Toast.makeText(getApplicationContext(), message, Toast.LENGTH_LONG).show();
                                Log.i("LOG", "after error 102");
                            } else if (Integer.parseInt(status) == 103) {
                                Toast.makeText(getApplicationContext(), message, Toast.LENGTH_LONG).show();
                                Log.i("LOG", "after error 103");
                            }
                        }
                    }
                    catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            } else {
                txtError.setText("Wrong phone number");
            }

        }
    });

I think application crashes when its going to perform this line :

                    String result = Webservice.readUrl("http://192.168.10.110:2233/api/register", params);

and this is my webservice module :

public class Webservice {

public static String readUrl(String url, ArrayList<NameValuePair> params) {

    try {

        HttpClient client = new DefaultHttpClient();
        HttpPost method = new HttpPost(url);

        if (params != null) {
            method.setEntity(new UrlEncodedFormEntity(params));
        }

        HttpResponse response = client.execute(method);

        InputStream inputStream = response.getEntity().getContent();
        String result = convertInputStreamToString(inputStream);

        return result;
    }
    catch (ClientProtocolException e) {
        e.printStackTrace();
    }
    catch (IOException e) {
        e.printStackTrace();
    }

    return null;
}


public static String convertInputStreamToString(InputStream inputStream) {
    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
        StringBuilder builder = new StringBuilder();

        String line = "";

        while ((line = reader.readLine()) != null) {
            builder.append(line);
        }

        return builder.toString();
    }
    catch (IOException e) {
        e.printStackTrace();
    }

    return null;
}
}

Answer 1

The url for your webservice is local to your machine. The emulator works fine because possibly it is on the same network.

But this url: http://192.168.10.110:2233/ cannot be accessed by your device. That's why it is getting some timeout error and your application crashes.

If you want to test this on your device, maybe you need to use a common network or use wifi and some proxy tool like Charles

Hope the issue is clear to you now.

Answer 2

Have you given privileges to your application? Some security software will prevent you application from accessing network.

Answer 3

I find answer so i explain it for who will read this post later,

After android 3, we should use Asynctask for send and receive from webservice.

My emulator was android 2.2 and my device was android 4.4, so application worked perfect on emulator but crashes in device.

Answer 4

in line

                 String result = Webservice.readUrl("http://192.168.10.110:2233/api/register", params);

you must get ipconfig for your device (phone) not use same ip config for your emu