在javascript中，使用保留顺序拆分字符串

Question

hosts=".uk.com:hostname:@10.10.10.10/10:@[2001:db8:1/64]:@11.11.11.11/11:@[::2/24]"

In javascript, how do i split the above string("hosts") string like the following :

newhosts=.uk.com,hostname,@10.10.10.10/10,@[2001:db8:1/64],@11.11.11.11/11,@[::2/24]"

tried this :

var hosts, newhosts;
var ip6_hosts = [];
var ip6_re = /@\[(.*?)\]/g;

hosts=".uk.com:hostname:@10.10.10.10/10:@[2001:db8:1/64]:@11.11.11.11/11:@[::2/24]";
while ((match=ip6_re.exec(hosts)) != null)
    ip6_hosts.push(match[0]);
non_ip6_hosts=hosts.replace(ip6_re, '').replace(/:+/g, ':');
newhosts=ip6_hosts.concat(non_ip6_hosts.split(':'));

actual output :

newhosts=@[2001:db8:1/64],@[::2/24],.uk.com,hostname,@10.10.10.10/10,@11.11.11.11/11

expected output :

newhosts=.uk.com,hostname,@10.10.10.10/10,@[2001:db8:1/64],@11.11.11.11/11,@[::2/24]

but not sure how to preserve the order. is there any way to achieve an expected output ?

Answer 1

Can't You just say:

host = host.replace(/:+/, ',');

whenever you want to change it? I feel like this is too simple of an answer, comment if I'm not getting it.

Answer 2

You could try:

    var openbracket=0;
    for (i=0; i<hosts.length; i++)
    {
    if (hosts.substr(i,1) == '[') openbracket=openbracket+1;
    if (hosts.substr(i,1) == ']') openbracket=openbracket-1;
            if ((hosts.substr(i,1) == ':') && openbracket==0)
            {
            hosts = hosts.substr(0,i) + ',' + hosts.substr(i+1,hosts.length-i-1);
            }
    }

seems to work for me, though I'm not sure if there's a better method for changing the value of hosts. All it needs to do is insert the ',' at the location i. The above code adds everything to the left of the ':', a ',', and everything to the right of the ':'.

note: this assumes you don't want any ':' inside of brackets changed to a comma.
hope this helps.

Answer 3

以下应该工作：

hosts.replace(/([^:]{1})\:{1}([^:]{1})/g, '$1,$2')

Answer 4

Can you try this...

String.prototype.replaceAt=function(index, character) {
return this.substr(0, index) + character + this.substr(index+character.length);

}

hosts=".uk.com:hostname:@10.10.10.10/10:@[2001:db8:1/64]:@11.11.11.11/11:@[::2/24]"

hosts = hosts.split(':@').join(',@');

var re = /:\\w/g; var found = hosts.match(re);

hosts.replaceAt(found.index,',');

Answer 5

Try this.

 var hosts='.uk.com:hostname:@10.10.10.10/10:@[2001:db8:1/64]:@11.11.11.11/11:@[::2/24]'; hosts = hosts.replace(/:@/g, ':@@'); hosts = hosts.split(':@'); var hostDetails = hosts[0].split(':'); var newHost = hostDetails.concat(hosts.splice(1, hosts.length)); console.log(newHost);