比较bash中的两个字符串

Question

I'd like to compare two strings and then another two strings. So if $version is not equal to 5 and type is not equal to dbma OR if $version is not equal to 6 and $type is not equal to dbmy

I can't quite get the syntax right.

if [[ "${version}" != "5" ]] &&  [[ "${type}" != "dbma" ]] || [[ "${version}" != "6" ]] &&  [[ "${type}" != "dbmy" ]]
then
   xyz
else
   abc
fi

Can someone please help?

Answer 1

Assuming this is what you actually mean ...

if [[ ($version != 5 && $type != "dbma") || ($version != 6 && type != "dbmy") ]]

The [[ built-in allows parentheses and logical operators within the expression (whereas legacy [ had neither, and newer versions have -a and -o for "and" and "or", but no parentheses).