为什么这个程序会出现异常？

Question

I have this program and always get the exception in the try catch block as "Something Wrong" in the output. Why is it that the output skips to the catch? Here's the code:

import java.io.*;
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.List;

class pgm {
  public static void main(String[] args) {
    StringBuffer sa = new StringBuffer();
    StringBuffer n = new StringBuffer();
    StringBuffer sb = new StringBuffer();

    try {
      FileReader fr = new FileReader("1.txt");
      int i;

      while ((i = fr.read()) != -1) {
        n.append((char) i);
      }
      fr.close();
    } catch (Exception e) {
    }

    String[] lines = String.valueOf(n).split("\n");

    int x = lines.length;
    int count = 1, m = 0;

    try {
      FileWriter fw1 = new FileWriter("1a.txt");
      FileWriter fw2 = new FileWriter("1b.txt");

      String linea = Files.readAllLines(Paths.get("1.txt")).get(1);
      sa.append(linea);

      for (int i = 2; count <= x; i++) {
        String lineb = Files.readAllLines(Paths.get("1.txt")).get(count);
        String ab = lineb;
        ab = ab.replace("\n", "");
        count++;
        String linec = Files.readAllLines(Paths.get("1.txt")).get(count);
        ab += linec;
        sb.append(ab);
        count++;
        m = 0;

        for (int j = 0; j < 5; j++) {
          String lined = Files.readAllLines(Paths.get("1.txt")).get(count);
          if (lined == "\n") {
            count++;
            m++;
          } else {
            break;
          }
        }

        for (int j = 0; j < m; j++) {
          sa.append("\n");
          sb.append("\n");
        }

        String linee = Files.readAllLines(Paths.get("1.txt")).get(count);
        sa.append(linee);
      }

      String sa1 = String.valueOf(sa);
      String sa2 = String.valueOf(sb);

      fw1.write(sa1);
      fw2.write(sa2);
      fw1.close();
      fw2.close();
    } catch (Exception e) {
      System.out.println("Something wrong");
    }
  }
}

What is exactly causing the exception in the catch block?

Answer 1

是的，如果您不打算处理或重新抛出异常，则不应捕获它们。