[英]Adding two numbers when the user can enter an int and double
I need the program to run when a user enter for example 4 and 6.5 or vice versa. 我需要程序在用户输入例如4和6.5时运行,反之亦然。 i have the if else running only when its either or and when it tries to run it for both at the same time i get a error code like this : 我有if else只在其中的任何一个或当它试图同时运行它时,我得到一个像这样的错误代码:
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at class2.AddTwoNumbers.main(AddTwoNumbers.java:28)
Any assistance would be greatly appreciated 任何帮助将不胜感激
public class AddTwoNumbers {
public static void main(String[] args) {
Scanner inputSource = new Scanner(System.in);
Scanner runAgain = new Scanner(System.in);
int input1, input2, result;
double input3, input4, result2;
String answer = null;
do {
System.out.println("Please enter two numbers: ");
if(inputSource.hasNextInt()) {
input1 = inputSource.nextInt();
input2 = inputSource.nextInt();
result = input1 + input2;
System.out.println("The sum of " + input1 + " and " + input2 + " is " + result);
} else if (!inputSource.hasNextInt()){
input3 = inputSource.nextDouble();
input4 = inputSource.nextDouble();
result2 = input3 + input4;
System.out.println("The sum of " + input3 + " and " + input4 + " is " + result2);
} else if (inputSource.hasNextInt() || inputSource.hasNextDouble()){
input1 = inputSource.nextInt();
input3 = inputSource.nextDouble();
result2 = input1 + input3;
System.out.println("The sum of " + input1 + " and " + input3 + " is " + result2);
}
System.out.println("Do you want to run this again? Enter Y for Yes or N for No: ");
answer = runAgain.next();
} while (answer != "N");
inputSource.close();
}
}
In such case, it's makes more sense to read the inputs with double number = Double.parseDouble(inputSource.nextLine());
在这种情况下,使用double number = Double.parseDouble(inputSource.nextLine());
读取输入更有意义double number = Double.parseDouble(inputSource.nextLine());
. 。 This would work for both int
and double
inputs. 这适用于int
和double
输入。
Your code becomes as simple as : 您的代码变得如此简单:
double input1 = Double.parseDouble(inputSource.nextLine());
double input2 = Double.parseDouble(inputSource.nextLine());
double result = input1 + input2;
Beside that, change while (answer != "N");
除此之外,改变while (answer != "N");
to while (!answer.equals("N"));
to while (!answer.equals("N"));
. 。
use nextLine()
method instead of nextInt()
and parse it into double which will work for both int
and double
type 使用nextLine()
方法而不是nextInt()
并将其解析为double,这将适用于int
和double
类型
double result;
double input1=Double.parseDouble(inputSource.nextLine());
double input2=Double.parseDouble(inputSource.nextLine());
result=input1+input2;
and also change while (answer != "N");
并且同时改变while (answer != "N");
with while (!answer.equals("N"));// since your are comparing string not character
with while (!answer.equals("N"));// since your are comparing string not character
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