如何将两个记录插入到不同的表中，首先使用insert，然后从insert php mysql中进行选择

Question

My question is not easy to explain for myself, but I will train.

I can insert a record into a table´s column form a form with php to mysql without problems. This insert generates an auto_increment record in another column from the same table.

So I want to select this new auto_increment record and insert it in another table.

<?php
            // process form`enter code here`
            $db_host="myhost";
            $db_user="myuser";
            $db_password="mypassword";
            $db_name="mydbname";
            $db_table_name="table1";
            $db_table_name2="table2";

            $record1= utf8_decode($_POST['record1']);
            $record2= utf8_decode($_POST['redord2']);

            $db_connection = mysqli_connect($db_host,$db_user,$db_password,$db_name);

            if (!$db_connection) {
                die('Could not connect to the database');
            }
            //insert record1 into table1
            $insert_value = 'INSERT INTO `' . $db_name . '`.`'.$db_table_name.'` (`name`) VALUES ("' . $record1 . '")';

            $result1 = $db_connection->query($insert_value);

            //consult auto_increment column from table1
            $select_value = 'SELECT column FROM table1 WHERE name = "' . $record1 . '"';

           //insert record2 into table2 in a row where a column is like $record1 
            $insert_value2 = 'INSERT INTO `' . $db_name . '`.`'.$db_table_name2.'` (`column1, column2`) VALUES ("' . $record2. '","' . $select_value  . '") WHERE name = "'.$db_table_name2.'"';

            $result2 = $db_connection->query($select_value);

            mysqli_close($db_connection);

        ?>

Answer 1

$query="Insert Statement";
$RunQuery = $db_connection->prepare($query);

If you're using PDO, it's PDO::lastInsertId(). So if your database handle is called $link:

$LastID = $db_connection->lastInsertId();

Or, If you're using MySQLi, it's mysqli::$insert_id or mysqli_insert_id():

$LastID = $db_connection->insert_id;

Now, Use this $LastID in next Query.

For more info, check mysql_insert_id , mysql_query in PDO

$insert_value2 = 'INSERT INTO `' . $db_name . '`.`'.$db_table_name2.'` (`column1, column2`) VALUES ("'.$record2.'","'.$LastID.'") WHERE name = "'.$db_table_name2.'"';

$result2 = $db_connection->query($insert_value2);

Answer 2

The mysqli_insert_id() function returns the ID generated by a query on a table with a column having the AUTO_INCREMENT attribute.

If the last query wasn't an INSERT or UPDATE statement or if the modified table does not have a column with the AUTO_INCREMENT attribute, this function will return zero.

For example,

$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
$mysqli->query($query);
echo $mysqli->insert_id;