接受一切的正则表达式python

Question

I want to write a re that accepts everything that is between parenthesis. My re is: r''\\'([^&]+'\\')' (ingnore the '' in the backslash)

I had to put that random character so it will accept everything except that. How can I write it so it accepts EVERYTHING including that character. Thanks.

Answer 1

How about:

r'\([^)]+\)'

Because you don't want to accept the close parenthesis.

Also:

(Dot.) In the default mode, this matches any character except a newline. If the DOTALL flag has been specified, this matches any character including a newline.

So:

r'\(.+\)'

Might be what you are looking for.