为什么这段代码会给出运行时错误？

Question

There will be multiple integers in the input. You have to write a computer program to read each integer and print Even if the integer is divisible by 2, else print Odd. To help further, the number of integers (T) to read will be the first input to the computer program.

Input Format: First line of input contains count of integers: T. T>=1 After that, each line contains the integer N.

Sample Input:

2 4 5

Sample Output:

Even Odd

#include <stdio.h>

int main()
{   
    int i,T,a[10];/*Assuming Number of integers would be less than 10*/
    printf("Enter the Number of integers\n");
    scanf("%d",&T);
    for(i=0;i<T;i++)
    {
        scanf("%d",a[i]);
        printf("\n");
    }
    for(i=0;i<T;i++)
    {
        if(a[i]%2==0)
            printf("Even\n");
        else
            printf("Odd\n");
    }

    return 0;
}

Answer 1

You have scanf("%d",a[i]); . Scanf is looking for a pointer to an integer, and you're passing an integer (which is likely to be 0 since you haven't assigned anything; note also that zero is generally equal to NULL). You want scanf("%d",&a[i]); . Also note that your compiler should be giving you a warning about this... if using gcc, you should get in the habit of always compiling code with -Wall

Answer 2

Thanks everyone. I found out the error and used dynamic memory allocation for the program. This was the program I used. If somebody could help me cut down the code to few lines then please help.

#include<stdio.h>
int main()
{
    int i,*ptr,t;
    printf("Enter the count:");
    scanf("%d",&t);
    ptr=(int*)malloc(t*sizeof(int));
    if(ptr==NULL)
    {
        printf("Memory not allocated\n");
        exit(0);
    }
    if(t>=1)
    {
        for(i=0;i<t;++i)
        {
            printf("Enter Data:");
            scanf("%d",ptr+i);
        }
        for(i=0;i<t;i++)
        {
            if((*(ptr+i))%2==0)
                printf("%d is Even\n",*(ptr+i));
            else
                printf("%d is Odd\n",*(ptr+i));
        }
    }   
    return 0;   

}