[英]Python: create dictionary element as modified value of existing element at initialization step
Is there any way to achieve something like: 有什么办法可以实现以下目标:
test = {
'x' : 1,
'y' : test.get(x) + 1 }
This will obviously fail, because 'test' doesn't exist. 显然,这将失败,因为“测试”不存在。
# solution #1
test = {"x" : 1}
test["y"] = test["x"] + 1
# solution #1.1
test = {"x" : 1}
test.update(y=test["x"] + 1)
# solution #2
x = 1
test = {"x": x, "y": x+1}
# solution #3
# (will obviously break as soon as you want to use a callable as value...)
def yadda(**kw):
d = kw
for k, v in kw.items():
if callable(v):
d[k] = v(d)
return d
test = yadda(x=1, y=lambda d: d["x"] + 1)
# solution #4 - attempt at making #3 more robust
class lazy(object):
def __init__(self, f):
self.f = f
def __call__(self, d):
return self.f(d)
def yadda(**kw):
d = kw
for k, v in kw.items():
if isinstance(v, lazy):
d[k] = v(d)
return d
test = yadda(x=1, y=lazy(lambda d: d["x"] + 1))
From your comment it seems that you want this: 从您的评论看来,您想要这样做:
x = 'verylongline'
suffix = 'some suffix'
test = {
'x' : x,
'y' : x + suffix }
test['y'] = test['x'] + 1
如果要在x更新时更改y的值,则必须在def中使用此代码,并在x更新时调用def
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