预期的不合格 ID

Question

Im doing a random password generator but I have a problem at a switch.

From case 4 to case 18 it says there is an "Expected unqualified-id" and points the '=' sign but I can't get the error.

Is there a problem with the syntaxis or code?

My code:

switch (a) {
        case 0:
            char[1] = 'a';
            break;
        case 1:
            char[1] = 'b';
            break;
        case 2:
            char[1] = 'c';
            break;
        case 3:
            char[1] = 'd';
            break;
        case 4:
            char[1] = 'e';
            break;

Answer 1

Problem : You can not name your array char , because this is a reserved word in C++ .

Solution : Rename your array and try again.