[英]SQL select rows where id is the same
I want to select the following values with the same ID. 我想选择以下具有相同ID的值。 I basically have a submit form which stores its values and I want to display each submit.
我基本上有一个提交表单,用于存储其值,我想显示每个提交。 This is how the Databse Table looks like:
这是数据库表的外观:
| id | name | value |
------------------------------------
| 1 | venue_1 | New York |
| 1 | time_1 | 12:00 |
| 1 | costs_1 | 50€ |
| 2 | venue_1 | Berlin |
| 2 | time_1 | 15:00 |
| ... | ... | ... |
I want to display the values like this: 我想显示这样的值:
| Venue | Time | Cost |
------------------------------------
| New York | 12:00 | 50€ |
| Berlin | 15:00 | ... |
| A Venue | The time | cost |
My SQL queries in PHP look like this (Joomla): 我在PHP中的SQL查询如下所示(Joomla):
$db->setQuery('SELECT value FROM subrecords WHERE name = "venue_1"');
$venue = $db->loadColumn();
$db->setQuery('SELECT value FROM subrecords WHERE name = "time_1"');
$time = $db->loadColumn();
But when I loop through them to display them it doesn't match up: 但是当我遍历它们以显示它们时,它们不匹配:
foreach ($venue as $key => $val) {
$output .= "<tr>
<td>".$venue[$key]."</td>
<td>".$time[$key]."</td>
</tr>";
}
print($output);
I dont see through the logic here because as of now I just select all the venue_1 and time_1 etc and load the columns so I get every value but they need to be linked to each other so I can display them in the right way. 我在这里看不到逻辑,因为到目前为止,我只选择了所有placement_1和time_1等并加载列,所以我得到了每个值,但它们需要相互链接,以便可以正确的方式显示它们。
Where is my mistake? 我的错误在哪里? How can I link them through the ID maybe?
我如何通过ID链接它们?
If something is unclear tell me please I don't want to make it difficult for you to help me :) 如果不清楚,请告诉我,我不想让您难于帮助我:)
Here you can get all in one Query. 在这里,您可以一次查询所有数据。 When you delete the WHERE line you get the hole table
删除WHERE行时,您会得到孔表
SELECT
Coalesce ((CASE WHEN name = "venue_1" THEN value END),NULL) Vebue,
Coalesce ((CASE WHEN name = "time_1" THEN value END),NULL) Time,
Coalesce ((CASE WHEN name = "cost_1" THEN value END),0) Coast
FROM subrecords
WHERE id = 1
GROUP BY id;
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