通过在c中的用户输入创建字符串数组？

Question

I'm new to C so some clarification would be very helpful! I'm trying to use a scanner to ask my program for a series of words which I will store..what I have so far is,

     char[]listOfWords[9999]; //creates a large array of characters
     scanf("%s", listOfWords); //stores inputs into listOfWords

with this, I can access the first word easily, but it comes to a matter of accessing the second, and third words..any suggestion? For example, how my input was

 Hello how are you guys

I can access "Hello" no problem, but how would I call "how" and "are"

Answer 1

This - char[]listOfWords[9999]; is not a valid syntax to declare array.

You simply need to declare an array -

char s[100];  
fgets(s,100,stdin);  // take input and store it in s

And using strtok or sscanf you can extract separate words in different arrays .

Or you can use a 2-d array -

char s[100][100];

So if string stored in it is - Hello how are you guys

then by s[0] you will get Hello , s[1] will give how and similarly , other words in string.

Answer 2

Scanf() only accepts input for a single word.(not after space.)

To enter multiple words, you can use gets(string) or scanf("%[^\\n]", string).

Answer 3

Is your problem to read multiple words? Or just reading a full line? Also the declaration char[]listOfWords[9999] is wrong. If you all you want to do is read a line, you can try the following:

char buffer[1024];
fgets(buffer, 1024, stdin);

Answer 4

• Here is a code what you are looking fore,

   #include <stdio.h> int main() { char str[5][10]; printf("enter the strings...\\n"); for(int i =0; i < 5; i++) scanf("%s", str[i]); printf("All strings are...\\n"); for(int j =0; j < 5; j++) printf("%s\\n", str[j]); }