与IN运算符一起使用时，JPA CONCATE引发异常
[英]JPA CONCATE when used with IN operator throws Exception
问题描述
I am trying to run a complex JPQL QUERY which doesn't throws Exception and works weirdly. 
我正在尝试运行一个复杂的JPQL QUERY，它不会引发Exception并且工作异常。
So here is my query 所以这是我的查询
SELECT b.pk.col1, b.pk.col2
FROM table1 b
WHERE b.pk.col2 IN ('someString')
AND b.pk.col3 IN (0, 1, 2)
AND b.pk.sdate < :now
AND b.edate > :now
AND b.col4 = 1
AND EXISTS
(SELECT a.cmid
FROM table2 a
WHERE a.col1 = 5 AND a.col2 = b.pk.col1)
AND b.pk.col1 NOT IN
(SELECT a.pk.col1
FROM table3 a
WHERE CONCAT (a.pk.tagid, 'ayush') IN ('1ayush'))
For Some Reason it throws error on Last line. 由于某种原因，它在最后一行上引发错误。 Here is the error 这是错误
Exception data: org.apache.openjpa.persistence.ArgumentException: Encountered "b . pk . col1 NOT IN ( select a . pk . col1 FROM Table3 a where CONCAT ( a . pk . tagId , \\'ayush\\' ) IN (" at character 249, but expected: ["(", ")", "*", "+", ",", "-", ".", "/", ":", "<", "<=", "<>", "=", ">", ">=", "?", "ABS", "ALL", "AND", "ANY", "AS", "ASC", "AVG", "BETWEEN", "BOTH", "BY", "CONCAT", "COUNT", "CURRENT_DATE", "CURRENT_TIME", "CURRENT_TIMESTAMP", "DELETE", "DESC", "DISTINCT", "EMPTY", "ESCAPE", "EXISTS", "FETCH", "FROM", "GROUP", "HAVING", "IN", "INNER", "IS", "JOIN", "LEADING", "LEFT", "LENGTH", "LIKE", "LOCATE", "LOWER", "MAX", "MEMBER", "MIN", "MOD", "NEW", "NOT", "NULL", "OBJECT", "OF", "OR", "ORDER", "OUTER", "SELECT", "SET", "SIZE", "SOME", "SQRT", "SUBSTRING", "SUM", "TRAILING", "TRIM", "UPDATE", "UPPER", "WHERE", , , , , ].
I have broken the query into multiple lines for the clarity : 为了清楚起见，我将查询分为多行：
This is the query in one single line 这是一行中的查询
SELECT b.pk.col1, b.pk.col2
FROM table1 b
WHERE b.pk.col2 IN ('someString')
AND b.pk.col3 IN (0, 1, 2)
AND b.pk.sdate < :now
AND b.edate > :now
AND b.col4 = 1
AND EXISTS
(SELECT a.cmid
FROM table2 a
WHERE a.col1 = 5 AND a.col2 = b.pk.col1)
AND b.pk.col1 NOT IN
(SELECT a.pk.col1
FROM table3 a
WHERE CONCAT (a.pk.tagid, 'ayush') IN ('1ayush'))
I forgot to mention that if I try to use = instead of IN , the query works, however this was a demo query and I actually have to use a List there 我忘了提一下，如果我尝试使用=而不是IN ，则查询有效，但是这是一个演示查询，实际上我必须在其中使用列表
EDIT : This my new JPA QUERY to which I give a Collection rather than some hard coded value 编辑 ：这是我给我的新的JPA QUERY，而不是一些硬编码的值
SELECT b.pk.col1, b.pk.col2
FROM table1 b
WHERE b.pk.col2 IN ('someString')
AND b.pk.col3 IN (0, 1, 2)
AND b.pk.sdate < :now
AND b.edate > :now
AND b.col4 = 1
AND EXISTS
(SELECT a.cmid
FROM table2 a
WHERE a.col1 = 5 AND a.col2 = b.pk.col1)
AND (b.pk.col1 NOT IN
(SELECT a.pk.col1
FROM table3 a
WHERE CONCAT (a.pk.tagid, 'ayush') IN (:somelist)))
And I still get the same Exception 而且我仍然得到同样的异常
Exception data: org.apache.openjpa.persistence.ArgumentException: Encountered "b . pk . col1 NOT IN ( select a . pk . col1 FROM Table3 a where CONCAT ( a . pk . tagId , \\'ayush\\' ) IN" at character 249, but expected: ["(", ")", "*", "+", ",", "-", ".", "/", ":", "<", "<=", "<>", "=", ">", ">=", "?", "ABS", "ALL", "AND", "ANY", "AS", "ASC", "AVG", "BETWEEN", "BOTH", "BY", "CONCAT", "COUNT", "CURRENT_DATE", "CURRENT_TIME", "CURRENT_TIMESTAMP", "DELETE", "DESC", "DISTINCT", "EMPTY", "ESCAPE", "EXISTS", "FETCH", "FROM", "GROUP", "HAVING", "IN", "INNER", "IS", "JOIN", "LEADING", "LEFT", "LENGTH", "LIKE", "LOCATE", "LOWER", "MAX", "MEMBER", "MIN", "MOD", "NEW", "NOT", "NULL", "OBJECT", "OF", "OR", "ORDER", "OUTER", "SELECT", "SET", "SIZE", "SOME", "SQRT", "SUBSTRING", "SUM", "TRAILING", "TRIM", "UPDATE", "UPPER", "WHERE", , , , , ]. at org.apache.openjpa.kernel.jpql.JPQL.generateParseException(JPQL.java:9566) at org.apache.openjpa.kernel.jpql.JPQL.jj_consume_token(JPQL.java:9443) at org.apac
1 个解决方案
解决方案1
0 2015-09-21 12:41:45
"xxx IN yyy" should be " {someValue} IN {someCollection} ". "xxx IN yyy"应为“ {someValue} IN {someCollection} ”。 You don't have a collection on the right hand side, hence the exception. 您的右侧没有集合，因此是个例外。 If your query really does now have a collection on the right hand side (which it doesn't in your post) and you still get an exception then post the actual exception+stack trace. 如果您的查询现在确实确实在右侧有一个集合（它不在您的帖子中），并且您仍然收到异常，请发布实际的异常+堆栈跟踪。 If the "xxx" and "yyy" are supposed to be equal, then you use "=" 如果假定“ xxx”和“ yyy”相等，则使用“ =“
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